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MariettaO [177]
2 years ago
15

Simplify this question m=12

Mathematics
1 answer:
amm18122 years ago
3 0
12x12=144
3x144=432
The answer is 432.
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Can someone please help me with my homework and explain it to me I will mark as brainlyist
Keith_Richards [23]

Answer:

121.76

Step-by-step explanation:

the original price is 83.97. you would have to find 45% of that. you would do this by putting x/83.97= 45/100

multiply 45 and 83.97 to get 3778.65. then divide that by 100 to get 37.7865. Add that to 83.97 to get 121.7565. round it to the nearest hundreth to get the total of 121.76 dollars

mark as brainlyest and answer my question

8 0
2 years ago
Find the area of the composite figure.
Bad White [126]

Answer:

Area = 139.27 m²

Step-by-step explanation:

Area of the composite figure = area of rectangle + area of semicircle

= (L*W) + ½(πr²)

L = 10 m

W = 10 m

r = ½ of 10 = 5 m

Plug in the values

Area = (10*10) + ½(π*5²)

Area = 100 + 39.27

Area = 139.27 m²

7 0
2 years ago
What is the measure of Angle A
jeka94

Answer:

Step-by-step explanation:

7.5xsin(16.7)/2.5=0.8620815595

sin-1(0.8620815595)=59.55110984

7 0
2 years ago
Read 2 more answers
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
The professor of a business statistics class wanted to find out the average amount of time per week her students spent studying
zhenek [66]

Answer:

Cluster sample

Step-by-step explanation:

This is an example of a cluster sample. In a cluster sample, the examiner divides the population into groups (each one of these groups is called a cluster) and once the examiner has these clusters, takes one of them and recollects the data from ALL the members of that cluster. In this case, the teacher divided the class in 3 different groups and then selects one of these groups and asks the average amount of time per week he/she spent studying.

6 0
2 years ago
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