19 Hours.
Step-by-step explanation:
You worked 9 hours on Monday, 6 hours on Tuesday, and 5 hours and 30 minutes on Thursday. You spent 1 hour and 30 minutes on an unpaid lunch break. You will be paid for 19 Hours and 30 Minutes of work. Hope this helps.
Answer: Solving for f. Want to solve for x instead?
1 Remove parentheses.
f\times -2fx=3{x}^{2}-8x+7f×−2fx=3x
2
−8x+7
2 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x
a
x
b
=x
a+b
.
-{f}^{2}\times 2x=3{x}^{2}-8x+7−f
2
×2x=3x
2
−8x+7
3 Regroup terms.
-2{f}^{2}x=3{x}^{2}-8x+7−2f
2
x=3x
2
−8x+7
4 Divide both sides by -2−2.
{f}^{2}x=-\frac{3{x}^{2}-8x+7}{2}f
2
x=−
2
3x
2
−8x+7
5 Divide both sides by xx.
{f}^{2}=-\frac{\frac{3{x}^{2}-8x+7}{2}}{x}f
2
=−
x
2
3x
2
−8x+7
6 Simplify \frac{\frac{3{x}^{2}-8x+7}{2}}{x}
x
2
3x
2
−8x+7
to \frac{3{x}^{2}-8x+7}{2x}
2x
3x
2
−8x+7
.
{f}^{2}=-\frac{3{x}^{2}-8x+7}{2x}f
2
=−
2x
3x
2
−8x+7
7 Take the square root of both sides.
f=\pm \sqrt{-\frac{3{x}^{2}-8x+7}{2x}}f=±√
−
2x
3x
2
−8x+7
8 Simplify \sqrt{-\frac{3{x}^{2}-8x+7}{2x}}√
−
2x
3x
2
−8x+7
to \sqrt{\frac{3{x}^{2}-8x+7}{2x}}\imath√
2x
3x
2
−8x+7
ı.
f=\pm \sqrt{\frac{3{x}^{2}-8x+7}{2x}}\imathf=±√
2x
3x
2
−8x+7
ı
9 Regroup terms.
f=\pm \imath \sqrt{\frac{3{x}^{2}-8x+7}{2x}}f=±ı√
2x
3x
2
−8x+7
Done- :)
f=±ı√ 2x 3x 2 −8x+7
Step-by-step explanation
Answer:
D. if it shifts down it's negative so you would subtract 5 from f(x)
since its the zeros it should be x -/+ something
(x-1)(x+1)(x+4)
multiply for standard form
((x^2)-1)(x+4)
x^3-x
+ x^2 -4
x^2 + x^2 -x -4
5x - 3y = 9
5x = 9 + 3y
5x - 9 = 3y
( 5x - 9 ) / 3 = y
y = ( 5 / 3x ) - ( 9 / 3 ) ( I just split the common denominator to individual parts )
y = 5 / 3x - 3
