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alisha [4.7K]
3 years ago
14

What is the formula for this?

Mathematics
1 answer:
zmey [24]3 years ago
8 0
Hey there! 

To find the area of a parallelogram, you multiply the length and the width together, the exact same method you would use to find the area of a rectangle or square.

The reason you would use the same area formula of a rectangle/square to find the area of a parallelogram would be that all rectangles are parallelograms (however, not all parallelograms are rectangles).
**Rectangles are a special kind of parallelogram: they are parallelograms with right angles formed in the corners of the figure.

Another thing to keep in mind is to imagine this: if you were to split the parallelogram from the top left corner straight down, you will get a triangular figure. If you were to move this triangular figure to fill in the right slanted part of the parallelogram, you would have a rectangle.

Now, to solve for the area. Because the formula is A=Base (or the length)*Height (or the width), you should have this expression:
A=20*27

This would simplify to 540 cm squared, which would be your answer.

Hope this helps and have a wonderful day! :)
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Ayuda Estoy En Examen:(
guapka [62]

Usando la división de términos con la <u>misma base y diferentes exponentes</u>, se encuentra que la expresión simplificada está dada por:

k^{-5}l^{-8}n^6a^{-4} = \frac{n^6}{k^5l^8a^4}

<h3>¿Cómo dividir términos con la misma base y diferentes exponentes?</h3><h3 />

Para hacer la división, mantenemos la base y restamos los exponentes.

En este problema, la división es dada por:

\frac{-k^6l^1n^9}{-k^{11}l^9n^3a^4}

Por lo tanto, el resultado es:

k^{6-11}l^{1-9}n^{9-3}a^{0-4} = k^{-5}l^{-8}n^6a^{-4} = \frac{n^6}{k^5l^8a^4}

Como tanto el numerador como el denominador son negativos, la división es positiva.

Puede-se aprender más a cerca de la división de términos con la <u>misma base y diferentes exponentes</u> en brainly.com/question/15722035

#SPJ1

6 0
2 years ago
Hello, may I please have some help on these 4 questions? Thanks very much! {Also, if you could answer them quick, that would be
wlad13 [49]
1.

Parallelogram with base a = 20 in. and height h = 16 in.
Triangle with base a = 20 in. and height b = 8 in.

so:

A = A_P+A_T=a\cdot h+\frac{1}{2}\cdot a\cdot b=20\cdot16+\frac{1}{2}\cdot20\cdot8=320+80=\\\\=\boxed{400\text{ in}^2}

2.

Trapezoid with base b₁ = 14 cm, base b₂ = 4 cm and height h = 10 cm
Triangle with base b₁ = 14 cm and height x = 18 cm - 10 cm = 8 cm

so:

A=A_T+A_\Delta=\frac{1}{2}\cdot(b_1+b_2)\cdot h+\frac{1}{2}\cdot b_1\cdot x=\\\\=&#10;\frac{1}{2}\cdot(14+4)\cdot 10+\frac{1}{2}\cdot 14\cdot8=\frac{1}{2}\cdot18\cdot 10+\frac{1}{2}\cdot 14\cdot8=90+56=\\\\=\boxed{146\text{ cm}^2}

3.

We have three rectangles:

A=A_1+A_2+A_3=1\cdot 4+6\cdot5+18\cdot6=4+30+108=\boxed{142\text{ ft}^2}

4.

Area of a circle:

A_\circ=\pi\cdot r^2=3.14\cdot5^2=3.14\cdot25=78.5 \text{ cm}^2

Area of a rectangle:

A_R=8\cdot 6=48\text{ cm}^2

Area of the shaded region:

A=A_\circ-A_R=78.5-48=\boxed{30.5\text{ cm}^2}


3 0
3 years ago
Please help ASAP with this Problem.
Romashka-Z-Leto [24]
WOW!, x actually = 23 I HOPE IT HELPS ENOUGH TO MARK ME AS BRAINLIEST!!!

6 0
3 years ago
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