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3 years ago

Which is the best estimate of the correlation coefficient for the scatter plot?

Mathematics

1 answer:

BARSIC [14]3 years ago

7 0

The best estimate for this correlation would be B) 0.9.

We can see that the number is constantly going up, which would throw out the D answer.

We can also see that for every time the x goes up 1, the y goes up a little less than one. We can see that in the ordered pairs that exist on the graph such as (3, 2), (8, 6) and (2.1, 1.9).

Since the y values are just lower than the x, the correlation would be just under one. Therefore, 0.9 is an accurate estimation.

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4 years ago

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4 years ago

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3 years ago

what two- dimensional shape is formed by a cross section of the cube shown if the cross section passes through the midpoints of

Nostrana [21]

<h2>Answer:</h2>

C= equilateral triangle

<h2>Step-by-step explanation:</h2>

To find this answer we need to know what a cube is. A cube is a prism whose sides all have the same length. It's something like the three dimensional version of a square. In the figure below, we have labeled each length of the cube as $x$ . Also, the vertex we taken is in blue color, so we need to find each side length of the triangle. Since the cross section passes through the midpoints of three edges that intersect at the same vertices of the cube, then:

$L_{1}=\sqrt{(\frac{x}{2})^2+(\frac{x}{2})^2} \\ \\ L_{1}=\sqrt{\frac{x^2}{4}+\frac{x^2}{4}} \\ \\ L_{1}=\sqrt{\frac{2x^2}{4}} \\ \\ L_{1}=\sqrt{\frac{x^2}{2}} \\ \\ L_{1}=\frac{x}{\sqrt{2}} \\ \\ L_{1}=\frac{x}{\sqrt{2}}\frac{\sqrt{2}}{\sqrt{2}} \\ \\ L_{1}=\frac{\sqrt{2}x}{2}$

Since this is a cube, then it is true that:

$L_{1}=L_{2}=L_{3}=\frac{\sqrt{2}x}{2}$

<em>Since the side lengths have the same value, this is an equilateral triangle.</em>

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4 years ago