Ask question

Ask question

All categories

3 years ago

14

There are 2 times as many girls as boys in my class. There are a total of 22 students. How many more boys than girls are in the

class?

1 answer:

mote1985 [20]3 years ago

8 0

11 more boys than girls in your class

You might be interested in

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$

At t = 0

$C(0) = 8(e^{(0)}-e^{(0)}) = 0$

At t = 2

$C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185$

At t = 12

$C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059$

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

4 0

3 years ago

HELP MEEE OMGGGG JESSUS AMENNN

irina1246 [14]

Answer:

Answers in the pics

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)

8 0

3 years ago

Can someone please tell me what 597 ➗ 5 is

BigorU [14]

Answer:

119.4

Step-by-step explanation:

Big Brain Dude <:

5 0

3 years ago

Please answer correctly !!!!!!!will mark 50 points !!!!!!!!!!!!!!!!

kirill115 [55]

This is an infinite loop display

3 0

3 years ago

If 32^2c=8^c what is the value of c? 1 2 3 5

Elina [12.6K]

Answer:

as written, c ≈ 0.000979 or c = 4
alternate interpretation: c = 0

Step-by-step explanation:

<em>As written</em>, you have an equation that cannot be solved algebraically.

(32^2)c = 8^c

1024c = 8^c

1024c -8^c = 0 . . . . . . rewrite as an expression compared to zero

A graphical solution shows two values for c: {0.000978551672551, 4}. We presume you're interested in c = 4.

___

If you mean ...

32^(2c) = 8^c

(2^5)^(2c) = (2^3)^c . . . . rewriting as powers of 2

2^(10c) = 2^(3c) . . . . . . . simplify

10c = 3c . . . . . . . . . . . . . .log base 2

7c = 0 . . . . . . . . . . . . . . . subtract 3c

c = 0 . . . . . . . . . . . . . . . . divide by 7

7 0

3 years ago