The length of the hypotenuse is 20 cm.
The shorter side of the triangle is 18 cm and each of the longer sides are 54 cm
<u>Solution:</u>
Given that triangle has perimeter of 126 cm
Let the length of the shorter side of the triangle be "a"
The 2 longer sides are 3 times as long as the shortest side
So length of 2 longer sides = 3(length of the shorter side)
length of 2 longer sides = 3a
<em><u>The perimeter of triangle is given as:</u></em>
perimeter of triangle = length of the shorter side + length of 2 longer sides
perimeter of triangle = a + 3a + 3a
126 = a + 3a + 3a
7a = 126
a = 18
So length of shorter side = 18 cm
length of 2 longer sides are each = 3a = 3(18) = 54 cm
Thus, the shorter side of the triangle is 18 cm and each of the longer sides is 54 cm
Answer:
a) 72.25sec
b) 6.25secs
c) after 10.5secs and 2 secs
Step-by-step explanation:
Given the height reached by the rocket expressed as;
s(t)= -4t^2 + 50t - 84
At maximum height, the velocity of the rocket is zero i.e ds/dt = 0
ds/dt = -8t + 50
0 = -8t + 50
8t = 50
t = 50/8
t = 6.25secs
Hence it will reach the maximum height after 6.25secs
To get the maximum height, you will substitute t - 6.25s into the given expression
s(t)= -4t^2 + 50t - 84
s(6.25) = -4(6.25)^2 + 50(6.25) - 84
s(6.25) = -156.25 + 312.5 - 84
s(6.25) = 72.25feet
Hence the maximum height reached by the rocket is 72.25feet
The rocket will reach the ground when s(t) = 0
Substitute into the expression
s(t)= -4t^2 + 50t - 84
0 = -4t^2 + 50t - 84
4t^2 - 50t + 84 = 0
2t^2 - 25t + 42 = 0
2t^2 - 4t - 21t + 42 = 0
2t(t-2)-21(t-2) = 0
(2t - 21) (t - 2) = 0
2t - 21 = 0 and t - 2 = 0
2t = 21 and t = 2
t = 10.5 and 2
Hence the time the rocket will reach the ground are after 10.5secs and 2 secs
i hope this helps a little bit
Answer:
I am not sure about this question sry but u can try asking a tutor u don't need to use any points
