How much did each care package weigh?

Mathematics

1 answer:

kompoz [17]3 years ago

7 0

1. Let the variable be x, which will be the weight of each box.

2. The equation would be total = weight of each box multiplied by the number of boxes and then that gets added to the 7 pounds

52 = 4x + 7

3. 52 = 4x + 7

Subtract 7 from both sides:

45 = 4x

Divide both sides by 4:

X = 45/4

X = 11.25

4. The weight of each care package was 11.25 pounds.

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The width of a rectangle is 22 inches and the perimeter is at least 165 inches. what inequality could be used to find the minimu

Lera25 [3.4K]

The answer is D.

We know that a rectangle has two widths that are equal and two lengths that are equal. One width is 22, so the other one is also 22.

If you wanted to find the lengths, you would add both widths together (same as multiplying a width by two) and add that to the two lengths equaled to the perimeter.

So, 22 * 2 + 2x = perimeter of rectangle. We added all four sides together.

We know that the perimeter is at least 165, so 22 * 2 + 2x = 165. Here's the twist. They want the most minimum possible length. So, what answer choice gives you 165 or less for the most minimum or smallest length while still getting to 165?
That is D.
22 * 2 + 2x < = 165.
Hope this helped!

6 0

4 years ago

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On a coordinate plane, a line goes through (negative 3, negative 3) and (negative 1, 5).

slega [8]

Answer:

y=20

x=4

Step-by-step explanation:

Since you can plug the first 2 coordinates into the slope equation ( $\frac{y_{2}-y_{1}}{x_{2} -x_{1} }$ ) you will get 4 for the slope so for the equation for the parallel line you would get y=4x+4 and since the x=4 you could plug that in and you would get y=20 and x=4