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4 years ago

Which of the following is a solution of y - x > -3?

1 answer:

6 0

While there are no answers available to choose from, the correct pick would be any that has an x value that is less than 3 larger than the y value. For instance 1 and 3 would work.

y - x > -3
1 - 3 > -3
-2 > -3 (TRUE)

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Re-write the set W by listing its elements. Use the appropriate set notation.

Setler [38]

For this, we will use roster notation.

We know that x has to be an integer, which is any number not a fraction. We also know that x is greater than 3, but not equal to it, therefore 3 will not be included. Our set will start with 4.

Since there are many, many integers greater than 3, we only have to list the first 5 and then add "..." to show the pattern continues.

W = {4, 5, 6, 7, 8, ...}

7 0

3 years ago

I WILL GIVE BRAINLEST IF YOU HELP ME PLEASE

jeka94

(10x-2y)+(-3y)= 10x-5y
(10x-5y)-(2x-2y)= 8x-3y

ANSWER: 8x-3y

4 0

3 years ago

Read 2 more answers

How much is a 6% commission on a sale of $24,000?

WINSTONCH [101]

Answer:

$1440

Step-by-step explanation:

You just find 6% of $24,000.

24000 x 0.06 = 1440

$1440

3 0

3 years ago

Read 2 more answers

Show your work on the multiplication please

Nataly [62]

Answer:

Daniel has 6,174 pokemon cards:)

We know this because 18 x 343 is 6,174.

(Hope this helps)

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3 years ago

Read 2 more answers

Two hoses are filling a pool the first hose fills at a rate of x gallons per minute the second hose fills at a rate of 15 gallon

Zielflug [23.3K]

Answer:

B. (0, 5]∪(15,30] only (15,30] contains viable rates for the hoses.

Step-by-step explanation:

The question is incomplete. Find the complete question in the comment section.

For us to meet the pool maintenance company's schedule, the pool needs to fill at a combined

rate of at least 10 gallons per minute. If the inequality represents the combined rates of the hoses is 1/x+1/x-15≥10 we are to find all solutions to the inequality and identifies which interval(s) contain viable filling rates for the hoses. On simplifying the equation;

$\frac{1}{x} + \frac{1}{x-15} \geq \frac{1}{10}\\\\ find\ the \ LCM \ of \ the function \ on \ the \ LHS\\\\\frac{x-15+x}{x(x-15)} \geq \frac{1}{10}\\\\\frac{2x-15}{x(x-15)} \geq \frac{1}{10}\\\\10(2x-15)\geq x(x-15)\\\\20x-150\geq x^2-15x\\\\collect \ like \ terms\\-x^2+20x+15x - 150\geq 0\\$

$-x^2+35x-150 \geq 0\\\\multipply \ through \ by \ minus\\x^2-35x+150 \leq 0\\\\(x^2-5x)-(30x+150) \leq 0\\\\x(x-5)-30(x-5) \leq 0\\\\$

$(x-5)(x-30) \leq 0\\\\x-5 \leq 0 and x - 30 \leq 0\\\\x \leq 5 \ and \ x \leq 30$

The interval contains all viable rate are values of x that are less than 30. The range of interval is (0, 5]∪(15,30]. Since the pool needs to fill at a combined rate of <em>at least 10 gallons per minute</em> for the pool to meet the company's schedule, <em>this means that the range of value of gallon must be more than 10, hence (15, 30] is the interval that contains the viable rates for the hoses.</em>

6 0

3 years ago