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klio [65]
3 years ago
5

If l is parallel to m, what is the relationship between 3 and 7?

Mathematics
1 answer:
zvonat [6]3 years ago
4 0

Answer:

B.

Step-by-step explanation:

they are correseponding angles so that means that they aer congruent because the lines are parallel

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Question 3 (25 points) Shopping at Saver Mart, Lisa buys her children four shirts and three pairs of pants for $85.50. She retur
cupoosta [38]

The system of equations that represent the cost of x shirts, and y pairs of pants are 4x + 3y = 85.50 and 3x + 5y = 115.00. Option (a) is correct.

A system of equations or an equation system is a collection of simultaneous equations.

Given that Shopping at Saver Mart, Lisa buys her children four shirts and three pairs of pants for $85.50 and She returns the next day and buys three shirts and five pairs of pants for $115.00

Now we have to find the system of equation

Lisa buys her children four shirts and three pairs of pants for $85.50 is given by

4x + 3y = 85.50

She buys three shirts and five pairs of pants for $115.00 is given by

3x + 5y = 115.00

Therefore the system of equations that represent the cost of x shirts, and y pairs of pants are

4x + 3y = 85.50 and 3x + 5y = 115.00

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6 0
1 year ago
3000 divided by 69541329
FinnZ [79.3K]

Answer:

1000/23180443

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A spherical balloon currently has a radius of 19cm. If the radius is still growing at a rate of 5cm or minute, at what rate is a
miv72 [106K]

Answer:

22670.8 cm³/min

Step-by-step explanation:

Given:

Radius of the balloon at a certain time (r) = 19 cm

Rate of growth of radius is, \frac{dr}{dt}=5\ cm/min

The rate at which the air is pumped in the balloon can be calculated by finding the rate of increase in the volume of the balloon.

So, first we find the volume of the sphere in terms of 'r'. As the balloon is spherical in shape, the volume of the balloon is equal to the volume of a sphere. Therefore,

Volume of balloon is given as:

V=\frac{4}{3}\pi r^3

Now, rate of increase of volume is obtained by differentiating both sides of the equation with respect to time 't'.

Differentiating both sides with respect to time 't', we get:

\frac{dV}{dt}=\frac{d}{dt}(\frac{4}{3}\pi r^3)\\\\\frac{dV}{dt}=\frac{4\pi}{3}(3r^2)(\frac{dr}{dt})\\\\\frac{dV}{dt}=4\pi r^2(\frac{dr}{dt})

Now, plug in 19 cm for 'r', 5 cm per minute for \frac{dr}{dt} and solve for \frac{dV}{dt}. This gives,

\frac{dV}{dt}=4\pi (19 cm)^2(5\ cm/min)\\\\\frac{dV}{dt}=4\times 3.14\times 361\times 5\ cm^3/min\\\\\frac{dV}{dt}=22670.8\ cm^3/min

Therefore, the rate at which the air is being pumped into the balloon is 22670.8 cm³/min.

4 0
4 years ago
Marco has a summer job mowing lawns. If he mows two lawns on Peach Street for $15.32 each and four lawns on Onion Street for $12
lord [1]

Answer:

$82.56

Step-by-step explanation:

Earnings for mowing 2 lawns on Peach St

= 2 x $15.32

= $30.64

Earnings for mowing 4 lawns on Onion St

= 4 x $12.98

= $51.92

Total earnings

= $30.64 + $51.92

= $82.56

5 0
3 years ago
Read 2 more answers
A car's cooling system has a capacity of 20 quarts. Initially, the system contains a mixture of 3 quarts of antifreeze and 17 qu
Pachacha [2.7K]

Answer:

1.10 quarts

Step-by-step explanation:

We are given that

Capacity of system=20 quarts=\frac{20}{4}=5 gal

1 gallon=4 quarts

Initially mixture contains

Antifreeze=3 quarts=\frac{3}{4}=0.75 gal

Water=17 quarts=\frac{17}{4}=4.25 gal

Water runs in to the system=1gal/min

We have to find the antifreeze in the system at the end of 5  minutes.

Concentration inflow=0

Let Concentration outflow=x

Rate of system=Concentration inflow(water inflow rate)-Concentration outflow(water outflow rate)

\frac{dx}{dt}=0\times 1-\frac{1}{5} x=-\frac{x}{5}

\frac{dx}{x}=-\frac{dt}{5}

Taking integration on both sides

\int\frac{dx}{x}=-\frac{1}{5}\int dt

ln x=-\frac{1}{5}t+C

x=3 and t=0

ln 3=C

ln x-ln 3=-\frac{1}{5}t

ln\frac{x}{3}=-\frac{1}{5}t

Using formula

ln m-ln n=ln\frac{m}{n}

\frac{x}{3}=e^{-0.2t}

x=3e^{-0.2t}

Substitute t=5

x=3e^{-0.2\times 5}=3e^{-1}=1.10

Hence, in the end of 5 minute ,the antifreeze in the system=1.10 quarts

7 0
4 years ago
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