Answer: 0.0241
Step-by-step explanation:
This is solved using the probability distribution formula for random variables where the combination formula for selection is used to determine the probability of these random variables occurring. This formula is denoted by:
P(X=r) = nCr × p^r × q^n-r
Where:
n = number of sampled variable which in this case = 21
r = variable outcome being determined which in this case = 5
p = probability of success of the variable which in this case = 0.31
q= 1- p = 1 - 0.31 = 0.69
P(X=5) = 21C5 × 0.31^5 × 0.69^16
P(X=5) = 0.0241
Answer:
0.36 = 36% probability that the land has oil and the test predicts it
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
45% chance that the land has oil.
This means that 
He buys a kit that claims to have an 80% accuracy rate of indicating oil in the soil.
This means that 
What is the probability that the land has oil and the test predicts it?
This is
. So


0.36 = 36% probability that the land has oil and the test predicts it
NO.....9.66% less than $18,000 is $16,261.20
230×12= $2,760
68 divided by 85 multiply by 100
68/85=0.8 x 100= 80%