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4 years ago

2007 divided by j = 223

Mathematics

1 answer:

Effectus [21]4 years ago

8 0

J = 9 because 2007 / 223 = 9, and when you multiply 223 x 9, you get 2007

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2y – 9x = 4 ......................

alekssr [168]

Answer:

y=9/2x+2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Solve: sin5x - cos2x + sin x = 0.

mote1985 [20]

Answer:

x = 10 , 45 degrees.

Step-by-step explanation:

This seems a tricky one .

I guess we can use sin A + sin B = 2 sin (A+B)/2 cos (A - B) / 2

so sin 5x + sin x = 2 sin 3x cos 2x so our equation becomes

2 sin 3x cos 2x - cos 2x = 0

cos 2x ( 2 sin 3x - 1) = 0

so 2 sin 3x = 1

sin 3x = 1/2

giving 3x = 30 degrees and x = 10 degrees

or cos 2x = 0

so 2x = 90

giving x = 45 degrees.

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3 years ago

I need help on this question

tatiyna

It is a right agn have a good day

6 0

3 years ago

M=110 what is m, the measure in degree s of third angle m=40 m=70 m-30

Ymorist [56]

M=70 cause 180-110=70

8 0

3 years ago

A club consists of 21 Republicans and 25 Democrats. If four people are chosen at random to be on a committee, what is the proba

Allushta [10]

Answer:

88.58% probability that at least one person from each political party will be chosen

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Also, the order which the people are chosen is not important. So the combinations formula is used to solve this problem.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

If four people are chosen at random to be on a committee, what is the probability that at least one person from each political party will be chosen?

Either only Republicans or Democrats are chosen, or at least one member from each party is chosen. The sum of these probabilities is 100%.

The easier way to solve this is first finding the probability that members are only from one party.

Probability of having members from only one party:

Desired outcomes:

Only Democrats:

4 from a set of 25.

Only Republican:

4 from a set of 21.

$D = C_{25,4} + C_{21,4} = \frac{25!}{4!21!} + \frac{21!}{4!17!} = 18635$

Total outcomes:

4 from 21+25 = 46 total members

$T = C_{46,4} = \frac{46!}{4!42!} = 163185$

Probability:

$p = \frac{D}{T} = \frac{18635}{163185} = 0.1142$

11.42% probability of having people from only one party in the committee

Probability of at least one person from each party:

p + 11.42 = 100

p = 88.58

88.58% probability that at least one person from each political party will be chosen

5 0

3 years ago