The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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#1 Mrs. Garcia is making 50 snacks for her 5th grade class. If she uses four 1-kilogram bags of dried fruit, how many of grams of fruit will she use for each snack?
1 kilogram is equal to 1000 grams.
4 kilograms is equal to 4000 grams.
You would need to divide the 4000 total grams by the 50 snack to get how many grams would be in each snack.
So you would do..
4000grams/50snacks = 80 grams each snack.
#3 Toni's recipe also calls for seasonings. She needs to stir in 215 milligrams of pepper and 437 milligrams of salt. What is the difference between the total amount of seasonings and 1 gram?
215 milligrams is equal to 0.215 grams
437 milligrams is equal to 0.437 grams
So you would add these two together
0.215 + 0.437 = 0.652 grams
Then to find the difference you would subtract 0.652 grams from 1 gram
1 - 0.652 = 0.348
0.348 is the difference.
He would need to pay $44 for the purchase because
10% x $40 = $4
$40 + $4 = $44
hope this helped ((:
Answer:
Step-by-step explanation:
To find the distance between two points, 
and 
, you can use the following distance formula:
Plugging in the points from the problem, you'll get the following:
Answer:
<h2>
Reflection across the y-axis and 1 unit shift downside.</h2>
Step-by-step explanation:
Notice that shape A is in the second quadrant and shape B is in the first quadrant. That means there was a reflection across y-axis and then the figure was shifted one unit downside.
Therefore, the transformation was reflection across the y-axis and 1 unit shift downside. Which is a rigid transformation, because the shape and size didn't change.
