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bekas [8.4K]
3 years ago
7

A scale drawing has a scale of 2 cm :21 km. find the actual length for a drawing length of 4.5 cm

Mathematics
2 answers:
djverab [1.8K]3 years ago
7 0
The correct answer is C! Because 21/2 = 10.5 and 10.5 x 4.5 = 47.25
tino4ka555 [31]3 years ago
6 0

The answer to this equation would be option C.47.25

hope this helps

:D :)

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Need help on 9 don’t know if I did it right or not but I need help :p
solmaris [256]

Answer:

9b) -8 = y

9a) 72° = <em>m</em>∠<em>ABC</em>

Step-by-step explanation:

Since you have an angle trisector, in this case, <em>m</em>∠<em>CBE</em><em> </em>≅ <em>m</em>∠<em>DBA,</em><em> </em>therefore you <em>set</em><em> </em><em>x</em><em> </em>equal to 8, plus, according to Morley's Trisector Theorem, all three angles form an equilateral triangle, so <em>m</em>∠<em>BOC</em><em> </em>also has to equal 24°:

{8}^{2}  - 5(8) = 64 - 40 = 24 \\  \\ 6(8) - 24 = 48 - 24 = 24 \\  \\ 2(8) - y = 24 >> 16 - y = 24 >>  -8 = y

Then, <em>m</em>∠<em>ABC</em><em> </em>comes from multiplying 3 by 24 [three <em>twenty-</em><em>four</em>'s], which results in 72°.

I am joyous to assist you anytime.

4 0
3 years ago
Choose the correct symbol for interval notation when a value is to be included in the solution.
RoseWind [281]
Choose the correct symbol for interval notation when a value is to be included in the solution
A. Parenthesis



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4 0
3 years ago
Read 2 more answers
From the airport hanger H, an areoplane A is 18km away on the bearing of 115° while another aeroplane B is 29km away on a bearin
maks197457 [2]

The difference in distance between Aero plane A and B is; 34.67 km

<h3>How to calculate bearing?</h3>

To get the bearing;

∠H = (115 - 90) + (270 - 203)

∠H = 92°

Then, we will use cosine rule to get the distance between both Planes A and B.

d_ab = √(18² + 29² - 2(18 * 29) * cos 92)

d_ab = √(324 + 841 + 36.435)

d_ab = 34.67 km

Read more about bearing at; brainly.com/question/22518031

#SPJ1

6 0
2 years ago
A stone is a British unit of weight equivalent to 14 pounds. After losing 1 1/2 stone. Jim is now 85% of his original weight. Wh
evablogger [386]

Answer:

Jim's current weight = 119 pounds

Step-by-step explanation:

1 Stone = 14 pounds

1\frac{1}{2} stone = 1.5 stone

1.5 stone = 1.5 (14 pounds) = 21 pounds

Jim lost 21 pounds

Let X be Jim's Original Weight

Y be his present weight

As per given statement in the Question:

After losing 1.5 stones (21 pounds of weight) Jim now weighs Y

Present weight = original weight - 21

Y = X -21     <u>                                                    Equation 1</u>

Also Current Weight = 85 % (Original weight)

Y = 85 % (X) =\frac{85X}{100}

Y=\frac{85X}{100}

put in Equation 1

\frac{85X}{100} = X-21

85X = (X-21) 100

85 X = 100 X -2100

or

2100 = 100 X - 85X

2100 = 15X

or

15 X = 2100

X=\frac{2100}{15}

X= 140 pounds ( Original Weight)

Current Weight = Y = Original weight - 21 <u><em>(From Equation 1)</em></u>

Y = X -21

Y = 140 -21

Y = 119 pounds (Current Weight)

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