Question

Help please!

Answer 1

we know that

The equation of the circle is of the form

$(x-h)^{2} +(y-k)^{2} =r^{2}$

where

$(h,k)$ is the center

$r$ is the radius

in this problem

we have

$(x+1.5)^{2} +(y+1)^{2} =9$

$(x+1.5)^{2} +(y+1)^{2}=3^{2}$

So

the center is the point $(-1.5,-1)$

the radius is $3$ units

using a graph tool

see the attached figure

Answer 2

Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the centre and r is the radius.
(x + 1.5)^2 + (y + 1)^2 = 9
(x - (-1.5))^2 + (y - (-1))^2 = 3^2
Center = (-1.5, -1) and radius is 3.