Ask question

Ask question

All categories

2 years ago

12

What is the answer to this

1 answer:

kobusy [5.1K]2 years ago

8 0

Cos(theta)=a/h
Cos(theta)=12/13
Theta=cos^-1(12/13)
Theta=22.62 degrees

Hope it helps

You might be interested in

I need help please asap 10 points!

earnstyle [38]

Answer:

1) Real Number

2)Whole Number

3)Irrational Number

4)Rational Number

5)Integers

6)Natural Numbers

4 0

3 years ago

Noah loves the Half-Tens facts and often uses them to solve multiplication problems. Make up a 2-digit by 3-digit multiplication

Stells [14]

Half Tens is a way of multiplying where we have to find the value of given numbers. First we double any 'one' of the two given numbers and multiply both to get an answer. Then we divide that answer by '2' to get the answer.

Lets take two numbers as 16 and 340

$16\times340=?$

Double the number 16

$32\times340=10880$

Now we will divide this by 2

$\frac{10880}{2}= 5440$

So, if we check $16\times340=?$ , it is 5440.

Similarly if we double the number 340, we get 680

Now, $16\times680=10880$

And 10880/2 = 5440

Hence, in both ways the answer is 5440.

6 0

3 years ago

A survey of teens suggested that 33% can name at least one professional baseball player, and 90% of those teens can also name at

loris [4]

Answer:

$d.\ 0.33 + 0.64 – (0.90)(0.33) = 0.673$

Step-by-step explanation:

Given

$P(Baseball) = 33\%$

$P(Baseball\ n\ Football) = 90\%$

$P(Football) = 64\%$

Required

$P(Baseball\ or\ Football)$

This is calculated as:

$P(Baseball\ or\ Football) =P(Baseball) + P(Football) -P(Baseball\ n\ Football)$

$P(Baseball\ or\ Football) = 0.33 + 0.64 - (0.90)(0.33)$

$P(Baseball\ or\ Football) = 0.33 + 0.64 - 0.297$

$P(Baseball\ or\ Football) = 0.673$

3 0

2 years ago

1/5 x 11 simplified if can

evablogger [386]

Answer:

2.2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One common ch

enot [183]

Answer:

$y=\frac{-7t^2+22t-7}{7t-22}$

Step-by-step explanation:

We are given that

Initial value problem

$y'=(t+y)^2-1$ , y(3)=4

Substitute the value $z=t+y$

When t=3 and y=4 then

z=3+4=7

$y'=z^2-1$

Differentiate z w.r.t t

Then, we get

$\frac{dz}{dt}=1+y'$

$z'=1+z^2-1=z^2$

$z^{-2}dz=dt$

Integrate on both sides

$-\frac{1}{z}dz=t+C$

$z=-\frac{1}{t+C}$

Substitute t=3 and z=7

Then, we get

$7=-\frac{1}{3+C}$

$21+7C=-1$

$7C=-1-21=-22$

$C=-\frac{22}{7}$

Substitute the value of C then we get

$z=-\frac{1}{t-\frac{22}{7}}$

$z=\frac{-7}{7t-22}$

$y=z-t$

$y=\frac{-7}{7t-22}-t$

$y=\frac{-7-7t^2+22t}{7t-22}$

$y=\frac{-7t^2+22t-7}{7t-22}$

8 0

4 years ago