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Anvisha [2.4K]
3 years ago
7

Can anyone maybe help me with this? Solve for x. Show your work. -1 /2x < -12

Mathematics
1 answer:
KIM [24]3 years ago
7 0
-1/2x < -12
(divide both side by -1/2, or -0.5 )
x > 24
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Please help me I need to get this right asap
lbvjy [14]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
Factor Polynomials<br> 6x^2+7x-3
Vesna [10]
Factoring is the process of finding the factors of polynomials

For our quadratic:
6x^2+7x-3&#10;=(2x+3)(3x-1)

I hope that helps!


I am with you if you faced any difficulties!






3 0
3 years ago
If x is a positive integer list the possible values of x
german

If the variable x is a positive integer, the list of possible values of x can be represented as; x >=1.

<h3>Positive integers</h3>

According to the question;

  • We are required to list the possible values of x provided the variable x is a positive integer.

On this note, the list of possible values of x is all numbers greater or equal to 1 in which case these numbers do not have a fractional component.

Read more on positive integers;

brainly.com/question/13292955

6 0
3 years ago
Maggie's brother is 3years younger than twice her age. The sum of their ages is 24. How old is Maggie?
Drupady [299]
B=bro's age
m=maggie's age


b=-3+2m

m+b=24

subsitute
m-3+2m=24
3m-3=24
add 3 both sides
3m=27
divide by 3
m=9


maggie is 9 year old
7 0
3 years ago
A student solves the following equation and determines that the solution is −2. Is the student correct? Explain. 3 a + 2 − 6a a2
Ganezh [65]

For this case, we have the following equation (according to the comments):

\frac{3}{a+2} - \frac{6a}{a^2-4}  = \frac{1}{a-2}

First, we factor the quadratic expression in the denominator:

\frac{3}{a+2} - \frac{6a}{(a-2)(a+2)}  = \frac{1}{a-2}

Then, we multiply both sides of the equation by (a-2) (a + 2):

\frac{3(a-2)(a+2)}{a+2} - \frac{6a(a-2)(a+2)}{(a-2)(a+2)}  = \frac{(a-2)(a+2)}{a-2}

Later, canceling similar terms we have:

3(a-2) - 6a = a+2

We do distributive property on the left side of the equation:

3a-6-6a=a+2

By grouping variables and constant terms we have:

3a - 6a -a = 2+6

Rewriting we have:

-4a=8

Finally, by clearing "a" we have:

a=-\frac{8}{4} a=-2

Note: the value of a is a extraneous solution because it makes the denominator of the original equation equal to zero.

Answer:

the student correct, but the value of a= -2 is an extraneous solution

8 0
4 years ago
Read 2 more answers
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