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3 years ago

What is the ratio of course to cups in a carton of milk

1 answer:

7 0

Well, the way I would do this is count the course and write that first, than put the 2 colins and than the carton of milk ratio. I hope this helped!

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Suppose the manager of a gas station monitors how many bags of ice he sells daily along with recording the highest temperature e

Maslowich

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Equation of regression line :

Yˆ = −114.05+2.17X

X = Temperature in degrees Fahrenheit (°F)

Y = Number of bags of ice sold

On one of the observed days, the temperature was 82 °F and 66 bags of ice were sold.

X = 82°F ; Y = 66 bags of ice sold

1. Determine the number of bags of ice predicted to be sold by the LSR line, Yˆ, when the temperature is 82 °F.

X = 82°F

Yˆ = −114.05+2.17(82)

Y = - 114.05 + 177.94

Y = 63.89

Y = 64 bags

2. Compute the residual at this temperature.

Residual = Actual value - predicted value

Residual = 66 - 64 = 2 bags of ice

4 0

3 years ago

What is the slope of a line parallel to the line containing (-6,1) and (3,-2)

timama [110]

Answer:

$m = -\frac{3}{9}$

Step-by-step explanation:

Use the following formula:

slope: $m = (y_{2} - y_{1})/(x_{2} - x_{1})$

Let:

$(x_{1} , y_{1}) = (-6 , 1)\\ (x_{2} , y_ {2}) = (3 , -2)\\$

Plug in the corresponding numbers to the corresponding variables:

$m = \frac{-2 - 1}{3 - (-6)}\\\\m = \frac{-3}{3 + 6}\\\\m = \frac{-3}{9}$

$m = -\frac{3}{9}$ is your answer.

3 0

3 years ago

I need help 5th grade

Trava [24]

6 5/6 just subtract 2 from the whole (8)

6 0

2 years ago

Read 2 more answers

A metal cylinder can with an open top and closed bottom is to have volume 4 cubic feet. Approximate the dimensions that require

Aleksandr-060686 [28]

Answer:

$r\approx 1.084\ feet$

$h\approx 1.084\ feet$

$\displaystyle A=11.07\ ft^2$

Step-by-step explanation:

<u>Optimizing With Derivatives </u>

The procedure to optimize a function (find its maximum or minimum) consists in :

Produce a function which depends on only one variable
Compute the first derivative and set it equal to 0
Find the values for the variable, called critical points
Compute the second derivative
Evaluate the second derivative in the critical points. If it results positive, the critical point is a minimum, if it's negative, the critical point is a maximum

We know a cylinder has a volume of 4 $ft^3$ . The volume of a cylinder is given by

$\displaystyle V=\pi r^2h$

Equating it to 4

$\displaystyle \pi r^2h=4$

Let's solve for h

$\displaystyle h=\frac{4}{\pi r^2}$

A cylinder with an open-top has only one circle as the shape of the lid and has a lateral area computed as a rectangle of height h and base equal to the length of a circle. Thus, the total area of the material to make the cylinder is

$\displaystyle A=\pi r^2+2\pi rh$

Replacing the formula of h

$\displaystyle A=\pi r^2+2\pi r \left (\frac{4}{\pi r^2}\right )$

Simplifying

$\displaystyle A=\pi r^2+\frac{8}{r}$

We have the function of the area in terms of one variable. Now we compute the first derivative and equal it to zero

$\displaystyle A'=2\pi r-\frac{8}{r^2}=0$

Rearranging

$\displaystyle 2\pi r=\frac{8}{r^2}$

Solving for r

$\displaystyle r^3=\frac{4}{\pi }$

$\displaystyle r=\sqrt[3]{\frac{4}{\pi }}\approx 1.084\ feet$

Computing h

$\displaystyle h=\frac{4}{\pi \ r^2}\approx 1.084\ feet$

We can see the height and the radius are of the same size. We check if the critical point is a maximum or a minimum by computing the second derivative

$\displaystyle A''=2\pi+\frac{16}{r^3}$