2x-438 = -438+2x= 2(x-219)
(7) m∠A = 52°
(8) m∠B = 117°
Solution:
(7) Let us first define the supplementary and complementary angles.
Supplementary angles: Two angles are said to be supplementary angles if their sum is add up to 180°
Complementary angles: Two angles are said to be complementary angles if their sum is add up to 90°
Given supplement of 142° = 180° – 142°
= 38°
Complement of ∠A = Supplement of 142°
⇒ Complement of ∠A = 38°
Measure of ∠A = 90° – 38°
= 52°
Hence m∠A = 52°.
(8) Given complement of 27° = 90° – 27°
= 63°
Supplement of ∠B = Complement of 27°
⇒ Supplement of ∠B = 63°
Measure of ∠B = 180° – 63°
= 117°
Hence m∠B = 117°.
Answer:
48.1 m³ available, 2.5m³ not available
Step-by-step explanation:
Tan(X) = 4.5/(5.8+1.7)
Tan X = 3/5
Hypotenuse² = 3² + 5² = 34
Sin X = 3/sqrt(34)
X = 30.96
1/sinX = 1.7/SinY
Y = 61.003°
Third angle: 180 - X - Y = 88.037
Volume
= ½ × 1.7 × 1 × sin(88.038) × 3
= .
= 2.548
= 2.5m³
Available for storage:
½×4.5×7.5×3 - 2.548
= 48.077 = 48.1 m³
