Answer:
I don't know if it would work for what you need but you could try scratch. (sorry if this isn't what you needed.)
Answer:
"public static void passAList(ArrayList<Integer> myList, int[] intArr)", is the correct answer for the above question.
Explanation:
Missing information :
- The option is missing but the question states "choose from the following". The correct defining syntax is defined above.
Detailed Explantion :
- The above question asked about syntax which takes the value of list and array as an argument.
- It is already defined in the above syntax.
- And the value is passed by the user at the time of function call.
- The array list is defined by the help of the ArrayList class and the array is defined by the help of the "[]" symbol.
Try reinstalling the app or check if your wifi connection is good, if everything’s good but the app still doesn’t work then just use the website
Answer: car | truck
Explanation: The pipe (|) symbol used can be used in regular expression to simply imply OR. This means when used in between expression, can be used to search for all matches of the strings in which it stands in between. In the scenario above, If the pipe symbol is located in between the two strings, such as [ cars | trucks], the expression returns possible occurrence of the strings cars and trucks. It may also be used to locate and return the occurrences of more than 2 strings, such as; string1 | string2 | string3
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}