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Anni [7]
3 years ago
6

Hewo everyone look at me I look ugly don't I​

Computers and Technology
2 answers:
aleksley [76]3 years ago
5 0

Answer:

ok then

Explanation:

Gwar [14]3 years ago
4 0

Answer:

Na, you look stunning...!!!! UwU

You might be interested in
Create a linked list for library patrons. Put at least 8 patrons in the list. (You should hard code this data.) Ask for a person
Evgesh-ka [11]

Answer:

Explanation:

#include <bits/stdc++.h>

using namespace std;

/* Link list node */

class Node

{

public:

string Name;

long Library_card_number;

string Street;

string City;

long Zip;

Node* next;

};

/* Given a reference (pointer to pointer) to the head

of a list and an int, push a new node on the front

of the list. */

void push(Node** head_ref,string name,long lcn,string street,string city,long zip)

{

/* allocate node */

Node* new_node = new Node();

/* put in the key */

new_node->Name = name;

new_node->Library_card_number = lcn;

new_node->Street = street;

new_node->City = city;

new_node->Zip = zip;

/* link the old list off the new node */

new_node->next = (*head_ref);

/* move the head to point to the new node */

(*head_ref) = new_node;

}

/* Checks whether the value x is present in linked list */

Node* search(Node* head, string x)

{

Node* current = head; // Initialize current

while (current != NULL)

{

if (current->Name == x)

return current;

current = current->next;

}

return NULL;

}

/* Driver program to test count function*/

int main()

{

/* Start with the empty list */

Node* head = NULL;

int x = 21;

/* Use push() to construct below list

14->21->11->30->10 */

push(&head, "Joe",1,"hippy Street","Bay area",2009);

push(&head, "Marie",2,"lippy street","san jose",2010);

push(&head, "Harry",3,"gippy Street","Bay area",2009);

push(&head, "Ashish",4,"dippy street","san jose",2010);

push(&head, "Zuck",5,"sippy Street","Bay area",2009);

push(&head, "Gates",6,"kippy street","san jose",2010);

push(&head, "Page",7,"pippy Street","Bay area",2009);

push(&head, "Brin",8,"dippy street","san jose",2010);

string name;

cout<<"Enter name of the person to search: ";

cin>>name;

Node* z = search(head,name);

if(z!=NULL){

cout<<"\nPerson found in the list"<<endl;

cout<<"Name: "<<z->Name<<endl;

cout<<"Library Card Number: "<<z->Library_card_number<<endl;

cout<<"Street: "<<z->Street<<endl;

cout<<"City: "<<z->City<<endl;

cout<<"Zip: "<<z->Zip<<endl;

}else{

cout<<"No person found with the name "<<name<<endl;

}

return 0;

}

7 0
3 years ago
Implement a Breadth-First Search of the people in the network who are reachable from person id 3980. You can implement BFS with
Gnoma [55]

Answer:

Check the explanation

Explanation:

import java.io.File;

import java.io.FileNotFoundException;

import java.util.LinkedList;

import java.util.Scanner;

import static org.junit.Assert.assertEquals;

/**

* CS146 Assignment 3 Node class This class is used for undirected graphs

* represented as adjacency lists The areFriends() method checks if two people

* are friends by checking if an edge exists between the two

*

*/

public class NetworkAdjList {

   // Initialize array with max number of vertices taken from SNAP

   static int max_num_vertices = 88234;

   static LinkedList<Integer>[] adjacencyList = new LinkedList[max_num_vertices];

   public static void createAdjacencyList() {

       // Initialize array elements

       for (int j = 0; j < max_num_vertices; j++) {

           adjacencyList[j] = new LinkedList<Integer>();

       }

       // Get file path of the 3980.edges file

       String filePath = "C:\\Users\\shahd\\Documents\\CS146\\Assignment 3\\Question 3\\Question3\\src\\a3\\3980.edges";

       File f = new File(filePath);

       // Use Scanner to read edges from the file and put it into adjacency list

       int a;

       int b;

       try {

           Scanner fileIn = new Scanner(f);

           while (fileIn.hasNext()) {

               a = fileIn.nextInt();

               b = fileIn.nextInt();

               adjacencyList[a].add(b);

               adjacencyList[b].add(a); // We need to add the edges both ways

           }

       } catch (FileNotFoundException e) {

           e.printStackTrace();

       }

   }

   public static boolean areFriends(int A, int B) {

       // If the adjacency list contains (A, B) edge, then return true, else false

       if (adjacencyList[A].contains(B)) {

           return true;

       } else {

           return false;

       }

   }

  private static void bfsHelper(boolean visited[], int currentNode, int dis, int sourceNode) {

       dis++;

       if(!visited[currentNode]) {

           visited[currentNode] = true;

           

           for(int neighbor: adjacencyList[currentNode]) {

               System.out.println(neighbor + " is at a distance of " + dis + " from " + sourceNode);

               bfsHelper(visited, neighbor, dis++, sourceNode);

           }

       }

   }

   public static void BFStraversal(int start) {

       boolean visited[] = new boolean[max_num_vertices];

       bfsHelper(visited, start, 0, start);

   }

   public static void main(String[] args) {

       /**

        * These test cases assume the file 3980.edges was used

        */

       createAdjacencyList();

       System.out.println("Testing...");

       assertEquals(areFriends(4038, 4014), true);

       System.out.println("1 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(3982, 4037), true);

       System.out.println("2 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(4030, 4017), true);

       System.out.println("3 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(4030, 1), false);

       System.out.println("4 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(1, 4030), false);

       System.out.println("5 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(4003, 3980), true);

       System.out.println("6 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(3985, 4038), false);

       System.out.println("7 of 7");

       System.out.println("Success!");

   }

}

**************************************************

8 0
3 years ago
13) An-Excel-file-is-generally called-a-l-an:
anzhelika [568]

Answer:

b) worksheet

Explanation:

An excel file is generally called a worksheet.

5 0
3 years ago
According to the government, employees have a right to understand the risks associated with the materials they work with.
Alex
True. They require a MSDS (Material Safety Data Sheet) for each chemical that a business receives.
3 0
3 years ago
Why CANON G1010 is the best choices than epson L3110 3in 1 Printer​
saveliy_v [14]

Answer:

I would say go with the canon as I have a better history with it than Epson

Explanation:

they both look similar and have similar features

3 0
3 years ago
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