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2 years ago

8

What inequality represents the verbal expression? all real numbers less than 70

1 answer:

neonofarm [45]2 years ago

5 0

For this case we have:

Let x be the variable that belongs to the real numbers. Then, all reals less than 70 can be expressed as:

$x$

The tip of the inequality is directed to the real numbers, since they tell us that they are less than 70, for 70 the inequality remains open.

Answer:

$x$

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X+y+z=12<br> 6x-2y+z=16<br> 3x+4y+2z=28<br> What does x, y, and z equal?

lianna [129]

Answer:

x = 20/13 , y = 16/13 , z = 120/13

Step-by-step explanation:

Solve the following system:

{x + y + z = 12 | (equation 1)

6 x - 2 y + z = 16 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Swap equation 1 with equation 2:

{6 x - 2 y + z = 16 | (equation 1)

x + y + z = 12 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/6 × (equation 1) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+(4 y)/3 + (5 z)/6 = 28/3 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Multiply equation 2 by 6:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+5 y + (3 z)/2 = 20 | (equation 3)

Multiply equation 3 by 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+10 y + 3 z = 40 | (equation 3)

Swap equation 2 with equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+8 y + 5 z = 56 | (equation 3)

Subtract 4/5 × (equation 2) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+(13 z)/5 = 24 | (equation 3)

Multiply equation 3 by 5:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+13 z = 120 | (equation 3)

Divide equation 3 by 13:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y+0 z = 160/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 2 by 10:

{6 x - 2 y + z = 16 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Add 2 × (equation 2) to equation 1:

{6 x + 0 y+z = 240/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract equation 3 from equation 1:

{6 x+0 y+0 z = 120/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 1 by 6:

{x+0 y+0 z = 20/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Collect results:

Answer: {x = 20/13 , y = 16/13 , z = 120/13

8 0

2 years ago

I need help with this question please

Mice21 [21]

Answer:

210 mph

Step-by-step explanation:

speed of jet = x

headwind: speed = x - 27

time taken = 1134.6/(x - 27)

tailwind: speed = x + 27

time taken = 1469.4/(x + 27)

same amount of time:

1134.6/(x - 27) = 1469.4/(x + 27)

Cross multiply,

1134.6(x + 27) = 1469.4(x - 27)

1134.6x + 30634.2 = 1469.4x - 39673.8

334.8x = 70308

x = 210 mph

4 0

1 year ago

Imagine a deck of 500 cards numbered from 1 to 500. If all the cards are shuffled randomly and you are asked to pick three cards

amm1812

Answer:

P = 1 / 6

Step-by-step explanation:

Given:-

- A deck has 500 cards

- Numbered from 1-500

Find:-

you are asked to pick three cards, one at a time, what's the probability of each subsequent card being larger than the previous drawn card

Solution:-

- Suppose we draw three cards. We don't care what they actually are, irrespective of number.

- Let the three numbers be a, b, c: Such that:

a < b < c.

- The total possible combinations with 3 numbered cards will be:

a b c

b a c

a c b

b a c

b c a

c a b

- We have 6 possibilities for 3 numbered cards. So the probability of of each subsequent card being larger than the previous drawn card would be:

P = 1 / possible combinations

P = 1 / 6

6 0

3 years ago