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Eva8 [605]
3 years ago
9

Plastic parts produced by an injection-molding operation are checked for conformance to specifications. Each tool contains 12 ca

vities in which parts are produced, and these parts fall into a conveyor when the press opens. An inspector chooses 3 parts from among the 12 at random. Two cavities are affected by a temperature malfunction that results in parts that do not conform to specifications.
a) How many samples contain exactly 1 nonconforming part?
b) How many samples contain at least 1 nonconforming part?
Mathematics
1 answer:
Ksju [112]3 years ago
4 0

Answer:

a) 45 possible outcomes

b) 55 possible outcomes

Step-by-step explanation:

Given:

- Total cavities = 12

- Selection = 3 parts

- Non-conforming cavities = 2

Find:

a) How many samples contain exactly 1 nonconforming part?

b) How many samples contain at least 1 nonconforming part?

Solution:

- The question asks for the use of combinations to express the outcomes for each scenario.

- For first part, we want the inspector to pick exactly one non-conforming part among 3 selected. So let us say that he has already chosen that one non conforming cavity. Now he has to make 2 more selections out of total conforming cavities = 12 - 2 = 10 conforming cavities. Hence, the total possible outcome is to chose 2 randomly from 10 conforming cavities.

                              ( Exactly 1 ) 10C2 = 45 possible outcomes

- The second part entails that at-least 1 non-conforming cavity is selected. To choose exactly 1 non conforming we calculated above. In the similar way calculate for selecting exactly 2 non-conforming cavities. The total possible outcome would be to choose from 10 conforming and we choose 1 from it:

                              ( Exactly 2 ) 10C1 = 10 possible outcomes

- Hence, for at-least 1 non conforming cavity being selected we same the above two cases calculated:

                             (At-least 1 ) =  ( Exactly 1 ) +  ( Exactly 2 )

                             (At-least 1 ) =  45 + 10 = 55 possible outcomes

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A.

  1. 2
  2. 0
  3. -4
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B.

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