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diamong [38]
3 years ago
13

Imagine drawing a figure with the following conditions: A quadrilateral with at least two right angles. Is the figure described

unique? Explain why or why not.
Mathematics
2 answers:
Mrac [35]3 years ago
6 0

Answer:

The figure is NOT unique.

 Imagine the following quadrilaterals:

 Rectangle

 Square

 We know that:

 Both quadrilaterals have at least two right angles.

 However, they are not unique because they depend on the lengths of their sides.

Step-by-step explanation:

To construct a quadrilateral uniquely, five measurements are required.  A quadrilateral can be constructed uniquely if the lengths of its four sides and a diagonal are given or  if the lengths of its three sides and two diagonals are given.

Just given two angles we cannot construct a unique quadrilateral.  There may be an infinite number of quadrilaterals having atleast two right angles

Examples:

All squares with varying sides

All trapezoids with two right angles

All rectangles with different dimensions

and so on.

Answer is

No.

Ahat [919]3 years ago
3 0

Answer: The figure described is not unique. Squares, rectangles, and trapezoids can all have two right angles. The description also allows for any size figure because it does not give any side lengths.

Step-by-step explanation: The Sample Answer

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Work out the interior angle of the octagon.<br> Please show the working out.
bija089 [108]

Answer:

135°

Step-by-step explanation:

formula = (n-2) * 180, whereby 'n' is the number of sides.

therefore, (8-2) * 180 = 1080°

1080° ÷ number of sides

= 1080° ÷ 8

= 135°

5 0
3 years ago
Read 2 more answers
The function y = x 2 - 10x + 31 has a ____
katrin [286]

Answer:

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

Step-by-step explanation:

In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.

Given function is:

f(x) = x^2-10x+31

Taking first derivative

f'(x) = 2x-10

Now the first derivative has to be put equal to zero to find the critical value

2x-10 = 0\\2x = 10\\x = \frac{10}{2} = 5

The function has only one critical value which is 5.

Taking 2nd derivative

f''(x) =2

f''(5) = 2

As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5

The value can be found out by putting x=5 in the function

f(5) = (5)^2-10(5)+31\\=25-50+31\\=6

Hence,

<u>The function y = x 2 - 10x + 31 has a minimum  value of 6</u>

Hence,

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

8 0
3 years ago
Please help!!!!!!!!!!
BabaBlast [244]

Answer:

12

Step-by-step explanation:

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7 0
3 years ago
Solve each system by substitution.<br> 5) 5x + 3y =-23<br> y = 4
docker41 [41]

Answer:

(- 7, 4 )

Step-by-step explanation:

Given the 2 equations

5x + 3y = - 23 → (1)

y = 4 → (2)

Substitute y = 4 directly into (1_

5x + 3(4) = - 23, that is

5x + 12 = - 23 ( subtract 12 from both sides )

5x = - 35 ( divide both sides by 5 )

x = - 7

Solution is (- 7, 4 )

3 0
3 years ago
2,200.00 simple interest rate of 3.4% how much money will there be in 5.5 years
Gelneren [198K]
Simple Interest = PRT
$2,200 x 0.034 x 5.5 = $411.40
2200 + 411.4 = $2611.40
7 0
4 years ago
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