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Reika [66]
3 years ago
14

If all four sides of an quadrilateral measure the same length, and one corner angle measures 90 degrees, circle the shape that t

he quadrilateral can b classified as
Rhombus
Square
Rectangle
Parallelogram
All the above
Mathematics
1 answer:
son4ous [18]3 years ago
7 0

Answer:

All of the above

Step-by-step explanation:

ALL of the above quadrilaterals have all these characteristics.

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I need help with these three
Ludmilka [50]
A. The relationship of <7 and <8 are that they are vertical angles, and are congruent.

B. Since vertical angles are congruent, you can form an equation where the two measurements equal each other. 

C. 5y-29=3y+19       then plug y into your equation: 5*24-29=91
    2y=48                   and so: <7 = 180-91=89 (and since <8 is congruent)
    y=24                     <8 also equals 89

Your second problem: 
complementary are two angles that add up to 90 degrees.
<B=x, <A=2x
2x+x=90
3x=90
x=30       so: <B=30 degrees, <A=60 degrees

Your third problem:
1. Since A and B are parallel, angle 3x+7 and angle 4x+5 are same-sided exterior angles. That means that they both add up to 180 degrees. So if you should add the two and make it equal 180
2. 3x+7+4x+5=180
    7x+12=180
    7x=168
    x=24
3. <6 is a corresponding angle with angle 3x+7, meaning that they are congruent. So plug x into 3x+7: 3*24+7=79 and since <6 is congruent to 3x+7, <6=79 degrees
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3 years ago
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How do you simplify (2xy2)3
pantera1 [17]
(2xy^{2})^{3} = (2xy^{2})(2xy^{2})(2xy^{2})
Now, we can just multiply it and obtain the result
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I used law presented on this example
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ivanzaharov [21]

Answer:

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Step-by-step explanation:

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You would do 1/3 * 24

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