All categories

2 years ago

Solve the system of equations using substitution y=2x+3 y=3x+1

2 answers:

7 0

1: Set the two equations equal to each other.
2x+3=3x+1
2: Subtract 1 from both sides.
2x-2=3x
3: Subtract both sides by 2x.
-2=x.
4: Plug in your x value.
y=2(-2)+3. Y=-1.

I hope I was able to help. Best of luck.

Archy [21]2 years ago

4 0

The Answer is y=2x+3 Because y = 3x + 1
2x + 3 = 3x + 1
2 = x and y = 7 || ordered pair(2,7) is the solution for this syetem

You might be interested in

The product of 4x and 0 is: 4x 4 0

ki77a [65]

Answer: 0

Step-by-step explanation:

Simply the answer is 0 because anything multiplied by 0 will result in 0

4x(0) = 0 

7 0

2 years ago

Which graph represents the line y=−3x+4?

harkovskaia [24]

Answer:

x=4/3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Point C is located at (1, 2) and point D is located at (−4, −2). Find the y value of the point that is 1 over 4 the distance fro

fomenos

If we use similar triangles ( as shown in the attachment ) we will see that the line CM is also 1/4 *( yC-yD)= 1/4*(2+2) = 1/4*4 =1
Answer: y-value of that point is A) y=1.

Download docx

4 0

2 years ago

Read 2 more answers

Relationship B has a greater rate than Relationship A. This graph represents Relationship A.

tester [92]

Answer:

Rate in relationship A = (6 - 3)/(8 - 4) = 3/4 = 0.75

For Table A: Rate = (3 - 1.2)/(5 - 2) = 1.8/3 = 0.6

For table B: Rate = (3.5 - 1.4)/(5 - 2) = 2.1/3 = 0.7

For table C: Rate = (4 - 1.6)/(5 - 2) = 2.4/3 = 0.8

For table D: Rate = (2 - 1.5)/(4 - 3) = 0.5/1 = 0.5

Therefore, the correct answer is option C.

4 0

2 years ago

How would you solve this equation? Please show steps

Serhud [2]

Simple....

you have: $3x= \sqrt{12-12x}$

So...first you know you're trying to find x..

But, you have a square root on one side...to remove this you'd have to square both sides--->>>

$(3x)^{2} = \sqrt{12-12x} ^{2}$

Leaving you with....

$9x^{2} =12-12x$

Move the terms over and set it equal to zero.

-->>

$9x^{2}+12x-12=0$

Factor out a 3...

$3( 3x^{2} +4x-4=0)$

What multiplies to -12 and adds to 4?

6*-2=-12

6+-2=4

Leaving you with...

$3(3x-2)(x+2)=0$

Remember you're solving for 0....

3x-2=0

3x-2=0
+2 +2

3x=2

$\frac{3x}{3} = \frac{2}{3}$

x= $\frac{2}{3}$

Then-->>

x+2=0

x+2=0
-2 -2

x=-2

Thus, your answer.

4 0

2 years ago