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omeli [17]
3 years ago
5

Solve the system of equations using substitution y=2x+3 y=3x+1

Mathematics
2 answers:
timama [110]3 years ago
7 0
1: Set the two equations equal to each other.
    2x+3=3x+1
2: Subtract 1 from both sides.
    2x-2=3x
3: Subtract both sides by 2x.
    -2=x.
4: Plug in your x value.
    y=2(-2)+3. Y=-1.

I hope I was able to help. Best of luck.

Archy [21]3 years ago
4 0
The Answer is y=2x+3 Because<span> y = 3x + 1
2x + 3 = 3x + 1
2 = x and y = 7 || ordered pair(2,7) is the solution for this syetem</span>
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a^2 + 12^2 = 13^2

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a^2 = 25

a = 5 cm

5 and 12 = 5 and 12

b) The two triangles are congruent because they have two side lengths in common. If at least two side lengths are the same on two triangles, then they are congruent. In addition, these triangles have one angle in common as well.

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8 0
3 years ago
ASAP PLEASE HELP!! 50 POINTS
svetlana [45]

Answer/Step-by-step explanation:

Total Distance = 3Ft

a) Determine the amplitude and period of a sinusoidal function that models the bobbing buoy.

Amplitude = 3/2 = 1.5         period = 10 second

\frac{0}{1} =\frac{2\pi }{b}      b=\frac{\pi }{5}         No ph. Shift

b) Write an equation of a function that models the buoy with x=0 at its highest point.​

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3 0
3 years ago
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Phoenix [80]

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4 0
2 years ago
A fence must be built to enclose a rectangular area of 45 comma 000 ftsquared. Fencing material costs $ 3 per foot for the two s
Tatiana [17]

Answer:

150 feet by 300 feet.

Step-by-step explanation:

The fence is to enclose a rectangular area of 45,000 ft squared.

If the dimensions of the rectangle are x and y

Area of a rectangle = xy

  • xy=45000
  • x=\frac{45000}{y}

Perimeter of the Rectangle =2x+2y

Fencing material costs $ 3 per foot for the two sides facing north and south and ​$6 per foot for the other two sides.

  • Cost of Fencing, C=$(6*2x+3*2y)=$(12x+6y)

Substitute x=\frac{45000}{y} into the Cost to get C(y)

C=12x+6y

C(y)=12(\frac{45000}{y})+6y\\C(y)=\frac{540000+6y^2}{y}

The value at which the cost is least expensive is at the minimum point of C(y), when the derivative is zero.

C^{'}(y)=\dfrac{6y^2-540000}{y^2}

\dfrac{6y^2-540000}{y^2}=0\\6y^2-540000=0\\6y^2=540000\\y^2=\frac{540000}{6} =90000\\y=\sqrt{90000}=300

Recall,

x=\frac{45000}{y}=\frac{45000}{300}=150

Since x=150, y=300

The dimensions that will be least expensive to build is 150 feet by 300 feet.

6 0
3 years ago
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