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mamaluj [8]
2 years ago
12

A small airplane flies 750 miles with an average speed of 250 miles per hour. 1.75 hours after the plane leaves, a Boeing 747 le

aves from the same point. Both planes arrive at the same time; what was the average speed of the 747?
Mathematics
1 answer:
sleet_krkn [62]2 years ago
4 0

Answer:

The average speed of the 747 was of 600 miles per hour.

Step-by-step explanation:

A small airplane flies 750 miles with an average speed of 250 miles per hour.

Velocity is distance divided by time, and here, we find the time of the small airplane. So

v = \frac{d}{t}

250 = \frac{750}{t}

250t = 750

t = \frac{750}{250}

t = 3

1.75 hours after the plane leaves, a Boeing 747 leaves from the same point. Both planes arrive at the same time;

This means that it traveled 750 miles in 3 - 1.75 = 1.25 hours.

What was the average speed of the 747?

v = \frac{d}{t} = \frac{750}{1.25} = 600

The average speed of the 747 was of 600 miles per hour.

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8+9p=9p-7  

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3 years ago
A bank's loan officer rates applicants for credit.
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Answer:

a=200 +0.253*50=212.65

So the value of height that separates the bottom 60% of data from the top 40% is 212.65. And rounded would be 212.7.  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the loan officer rates applicants for a credit of a population, and for this case we know the distribution for X is given by:

X \sim N(200,50)  

Where \mu=200 and \sigma=50

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.40   (a)

P(X   (b)

Both conditions are equivalent on this case.

As we can see on the figure attached the z value that satisfy the condition with 0.60 of the area on the left and 0.40 of the area on the right it's z=0.253. On this case P(Z<0.253)=0.60 and P(z>0.253)=0.4

If we use condition (b) from previous we have this:

P(X  

P(Z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.253

And if we solve for a we got

a=200 +0.253*50=212.65

So the value of height that separates the bottom 60% of data from the top 40% is 212.65. And rounded would be 212.7.  

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3 years ago
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