Ask question

Ask question

All categories

4 years ago

5

The improper fraction 8/5 is equivalent to

1 answer:

olga2289 [7]4 years ago

6 0

8/5

We have to just divide.

Here 1 is the quotient while 3 is the remainder when 8 is divided by 5.

So, 8/5 is also equal to 1 3/5.

Hope This Helps You!

You might be interested in

Three yards of fabric will be cut into pieces so that each piece is 8 inches long. How many pieces can be cut? (1 yard = 36 inch

In-s [12.5K]

You have 3 yards and each piece of fabric needs to be 8inches long. Convert yards into inches. Divide it by 8.

3yds= 108 inches
108/8= 13.5

You can cut 13.5 pieces of fabric.

Have a good day :)

6 0

3 years ago

Name each polynomial by degree amd number of terms<br>6p^4 + 10p^2

Volgvan

Two term quartic, or degree 4 polynomial

5 0

3 years ago

If f(x) = 3(x+ 5) +4/x, what is f(a+2)?

Eduardwww [97]

Answer:

B. 3(a + 7) + 3/(a + 2)

Step-by-step explanation:

Just substitute (a+2) in for every (x) in the equation:

f(a + 2) = 3 ((a + 2) + 5) + 4/(a+2)

= 3 (a + 7) + 4/(a+2)

4 0

3 years ago

Solve each system of equations (systems with 3 variables)

Natasha2012 [34]

Answer:

x = 2 , y = 5 , z = -1 You are correct!!!

Step-by-step explanation:

Solve the following system:

{9 x + 3 y - 4 z = 37 | (equation 1)

4 x + 3 y + 7 z = 16 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 4/9 × (equation 1) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+(5 y)/3 + (79 z)/9 = (-4)/9 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Multiply equation 2 by 9:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 1/9 × (equation 1) from equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - (16 y)/3 + (76 z)/9 = (-316)/9 | (equation 3)

Multiply equation 3 by 9/4:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - 12 y + 19 z = -79 | (equation 3)

Add 4/5 × (equation 2) to equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+(411 z)/5 = (-411)/5 | (equation 3)

Multiply equation 3 by 5/411:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 79 × (equation 3) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y+0 z = 75 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 2 by 15:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 3 × (equation 2) from equation 1:

{9 x + 0 y - 4 z = 22 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Add 4 × (equation 3) to equation 1:

{9 x+0 y+0 z = 18 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 1 by 9:

{x+0 y+0 z = 2 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Collect results:

Answer: {x = 2 , y = 5 , z = -1

5 0

3 years ago

Solve for b in (y^-9)^b=y^45

ElenaW [278]

Y^-9 * b = y^45 Divide by y^-9
b = $\dfrac{y^{45}}{y^{-9}}$

The law of powers says that if you have the same base (y in this case) and two different powers that are divided, you can subtract the denominator from the numerator (in this case)

b = $y^{45- - 9} = y^{54}$

8 0

4 years ago