Question

Which statements are true about the fully simplified product of (b – 2c)(–3b + c)? Check all that apply. The simplified product has 2 terms. The simplified product has 4 terms. The simplified product has a degree of 2. The simplified product has a degree of 3. The simplified product has a degree of 4. The simplified product, in standard form, has exactly 2 negative terms.

Answer 1

Answer:

The simplified product has a degree of 2.

The simplified product, in standard form has exactly 2 negative terms.

Step-by-step explanation:

$(b - 2c)(-3b + c)$

LEts multiply it using FOIL method

$b* -3b= -3b^2$

$b*c= bc$

$(-2c) * (-3b)= 6bc$

$(-2c) * c= -2c^2$

The product is $-3b^2 +bc+6bc-2c^2$

$-3b^2+7bc-2c^2$

The simplified product has a degree of 2.

It has two negative terms

Answer 2

Answer: The correct options are,

The simplified product has a degree of 2,

The simplified product, in standard form, has exactly 2 negative terms.

Step-by-step explanation:

Here, the given expression,

$(b-2c)(-3b+c)$

By distributive property,

$=(b-2c)(-3b)+(b-2c)(c)$

Again by distributive property,

$=b(-3b)-2c(-3b)+bc-2c(c)$

$=-3b^2+6bc+bc-2c^2$

$=-3b^2+7bc-2c^2$

Which is the simplified form of the given expression,

That having three terms in which two terms are negative and the degree ( The highest sum of the exponents of the variables) is 2,

Hence, the correct options are,

The simplified product has a degree of 2,

The simplified product, in standard form, has exactly 2 negative terms.