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3 years ago

What is 0.433 rounded to the nearest tenths

2 answers:

6 0

0.433 is already rounded to the hundredths so to round it to the nearest tenths, remove the last number.

Your answer is 0.43

Airida [17]3 years ago

3 0

0.43 is the answer to your question

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a multiplication that corresponds to each division 10 divided by 5=?, b. 4.5 divided by 3, 1/2 dvided by 4=?

katen-ka-za [31]

Answer:

10 divided by 5=2

2*5=10

4.5 divided by 3=1.5

3*1.5=4.5

1/2 divided by 4=1/8

4*1/8=4/8=1/2

6 0

2 years ago

I still dont understand how they got 50

patriot [66]

I’m lost cuz there ain’t no problem? Lol

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2 years ago

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A number increased by twelve

Anarel [89]

Answer:

X+12

Step-by-step explanation:

"Increased by" means addition.

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3 years ago

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What is the following simplified product? Assume x greater-than-or-equal-to 0

nlexa [21]

Answer:

$10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}$

Step-by-step explanation:

Remove perfect squares from under the radicals.

$(\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})\\\\=(\sqrt{10x^4})(2\sqrt{15x^4}) +(\sqrt{10x^4})(\sqrt{3x^3}) -(x\sqrt{5x^2})(2\sqrt{15x^4}) -(x\sqrt{5x^2})(\sqrt{3x^3})\\\\=2\sqrt{150x^8}+\sqrt{30x^7}-2x\sqrt{75x^6}-x\sqrt{15x^5}\\\\=\boxed{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}$

_____

The applicable rules of exponents are ...

(x^a)(x^b) = x^(a+b)

√(a^2) = a . . . . . . . for a > 0

(√a)(√b) = √(ab)

5 0

3 years ago

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At East Middle School, there are 585858 left-handed students and 609609609 right-handed students. The numbers of left- and right

lisabon 2012 [21]

Answer: C. Left-handed: 48 Right-handed: 504

E. Left-handed: 30 Right-handed: 315

Step-by-step explanation:

Here is the completed question:

At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed students at West Junior High are proportional to the numbers at East Middle School. Which of the following could be the numbers of left-handed and right-handed students at West Junior High?

A. Left-handed: 42 Right-handed: 483

B. Left-handed: 28 Right-handed: 378

C. Left-handed: 48 Right-handed: 504

D. Left-handed: 56 Right-handed: 560

E. Left-handed: 30 Right-handed: 315

Since it's direct proportion, we have to calculate the constant of proportionality which will simply be:

= 609 / 58 = 10.5

A. Left-handed: 42 Right-handed: 483

Constant = 483/42 = 11.5

Incorrect

B. Left-handed: 28 Right-handed: 378

Constant = 378/28 = 13.5

Incorrect

C. Left-handed: 48 Right-handed: 504

Constant = 504/48 = 10.5

Correct

D. Left-handed: 56 Right-handed: 560

Constant = 560/56 = 10

Incorrect

E. Left-handed: 30 Right-handed: 315

Constant = 315/30 = 10.5

Correct

Therefore, the correct options are C and E.

3 0

2 years ago

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