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lutik1710 [3]
4 years ago
14

Solve for Z, Y, W, and X

Mathematics
1 answer:
RUDIKE [14]4 years ago
4 0
Congruent sides have congruent angles so
w=70
Triangle angles =180 so
70+70+x=180
140+x=180
-140 both sides
x=40

supplimentary angles (angles that make up a line) =180 so
w+y=180
70+y=180
-70 both sides
y=110

triangle angles =180 so
110+25+z= 180
135+z=180
-135 both sides
z=45

w=70
x=40
y=110
z=45
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Consider the inequality 4x – 3 ≥ 13. Select four x-values that make the inequality true.
Neporo4naja [7]

Answer:

Step-by-step explanation:

Here are some steps to help you

Step 1

4x-3≥13  We are going to be simplifying

Step 2

4x-3≥13  Add 3 to the sides

4x≥16

Step 3

4x≥16  Divide them sides by 4

x≥4

So therefore your answer is x≥4

Hope this helps

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AlexFokin [52]

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Rewrite as y−k=a(x−h)2 or x−h=a(y−k)2. Find the vertex, focus, and directrix.<br> y−3=(2−x)^2
Talja [164]

Given:

The given equation is

y-3=(2-x)^2

To find:

The vertex, focus, and directrix.

Solution:

The equation of a parabola is

y-k=a(x-h)^2     ...(i)

where, (h,k) is vertex, \left(h,k+\dfrac{1}{4a}\right) and directrix is y=k-\dfrac{1}{4a}

We have,

y-3=(2-x)^2

It can be written as

y-3=(-(x-2))^2

y-3=(x-2)^2    ...(ii)

On comparing (i) and (ii), we get

h=2,k=3,a=1

Vertex of the parabola is (2,3).

Focus=\left(2,3+\dfrac{1}{4(1)}\right)

Focus=\left(2,3+\dfrac{1}{4}\right)

Focus=\left(2,\dfrac{13}{4}\right)

Therefore, the focus of the parabola is \left(2,\dfrac{13}{4}\right).

Directrix of the parabola is

y=3-\dfrac{1}{4(1)}

y=3-\dfrac{1}{4}

y=\dfrac{11}{4}

Therefore, the directrix of the parabola is y=\dfrac{11}{4}.

4 0
3 years ago
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