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aksik [14]
3 years ago
8

Model23 less than 55 on the number line

Mathematics
1 answer:
bulgar [2K]3 years ago
8 0
55-23=32 so 32 on the number line
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Functions and their Properties<br><br>Practice<br>Need help​
lilavasa [31]

Answer:

g(n-7)=\frac{n^{2}-14n+43}{7n-49}  → (a)

Step-by-step explanation:

We need to evaluate g(n - 7), where

  • g(x)=\frac{x^{2}-7}{7x}

Replace x by (n - 7) to evaluate it

∵ x = (n - 7)

∴ g(n-7)=\frac{(n-7)^{2}-6}{7(n-7)}

→ Let us find (n - 7)²

∵ (n - 7)² = (n - 7)(n - 7) = (n)(n) + (n)(-7) + (-7)(n) + (-7)(-7)

∴ (n - 7)² = n² + (-7n) + (-7n) + 49 = n² + -14n + 49

∴ (n - 7)² = n² - 14n + 49

→ Find 7(n - 7)

∵ 7(n - 7) = 7(n) - 7(7)

∴ 7(n - 7) = 7n - 49

→ Now let us write then in the form above

∵ g(n-7)=\frac{n^{2}-14n+49-6}{7n-49}

→ Add the like terms in the numerator

∴  g(n-7)=\frac{n^{2}-14n+43}{7n-49}

The correct answer is (a)

5 0
4 years ago
Clayton has saved $5.65 in dimes and quarters. He has 10 more quarters than dimes. How many of each denomination of coins does h
Ksju [112]

Answer: Dimes: 9

Quarters :19

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations using the information given:

He has 10 more quarters than dimes

Q = D +10

Clayton has saved $5.65 in dimes and quarters

0.25 Q + 0.10 D = 5.65

Where:

Q= number of quarters

D= number of dimes

Replacing the value of Q for (D+10) in the second equation:

0.25 (D +10)  + 0.10 D =5.65

0.25D + 2.5 +0.10D =5.65

0.25D + 0.10 D =5.65-2.5

0.35 D = 3.15

D = 3.15/0.35

D=9

Replacing the value of D by 13 in the first equation:

Q= D +10

Q =9 +10 =19

6 0
3 years ago
What is the nth term rule of the quadratic sequence below?
Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

<u>Given sequence</u>:

6, 20, 40, 66, 98, 136, ...

Calculate the <u>first differences</u> between the terms:

6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136

As the first differences are not the same, calculate the <u>second differences:</u>

14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38

As the <u>second differences are the same</u>, the sequence is quadratic and will contain an n² term.

The <u>coefficient</u> of the n² term is <u>half of the second difference</u>.

Therefore, the n² term is:  3n²

Compare 3n² with the given sequence:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

The second operations are different, therefore calculate the differences <em>between</em> the second operations:

3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18

As the differences are the same, we need to add 5n as the second operation:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2  +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2  &-2  & -2  \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0
2 years ago
If f(x)=2x^4-3x^3+2x^2+x-3, explain how you know that the equation f(x)=0 has at least one real root between x=1 and x=2
hodyreva [135]

Answer:

Step-by-step explanation:

by theorem :

f continu in [1 , 2]

f(1)×f(2) < 0 because : f(1) = -1 and f(2) = 15

so the equation f(x)=0 has at least one real root between x=1 and x=2

so :

7 0
3 years ago
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
nikdorinn [45]

Answer:

yo

Step-by-step explanation:

wassuh

4 0
4 years ago
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