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2 years ago

Please help. If f(x)= 2^x-1+3 and g(x)=5x-9 what is (f-g)(x)??

Mathematics

2 answers:

nata0808 [166]2 years ago

5 0

Answer:

2^-5x+12

Step-by-step explanation:

Readme [11.4K]2 years ago

4 0

( f + g ) (x) = –2x + 6

( f – g ) (x) = 8x – 2

( f × g ) (x) = –15x2 + 2x + 8

\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}(gf)(x)=4−5x3x+2

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3 years ago

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2 years ago

What is the factorization of 729^15+1000

Nesterboy [21]

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3 0

3 years ago

A flagpole is supported by a wire fastened 60 feet from its base. The wire is longer than the height it reaches on the flagpole.

maxonik [38]

Answer:

135.5ft

Step-by-step explanation:

THIS COMPLETE THE QUESTION

flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.

Let X be the length of the wire

Let y be the height of the pole

X= Y + 14

Y= X -14

We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)

Using Pythagoras theorem

X²= 60² + Y²

X² = 3600 + Y²

if we subsitute for Y we have

X² = 3600 + (X -14)²

X² = 3600 +X² -14X-14X+196

X²-X²+ 28X= 3600+196

28X= 3796

X= 3796/28

=135.5ft

hence length of the wire is 135.5ft

8 0

2 years ago