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Studentka2010 [4]
3 years ago
7

Please help. If f(x)= 2^x-1+3 and g(x)=5x-9 what is (f-g)(x)??

Mathematics
2 answers:
nata0808 [166]3 years ago
5 0

Answer:

2^-5x+12

Step-by-step explanation:

Readme [11.4K]3 years ago
4 0

( f + g ) (x) = –2x + 6

( f – g ) (x) = 8x – 2

( f  × g ) (x) = –15x2 + 2x + 8

<span>\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}<span><span>(<span><span>​g</span>​<span>​f</span><span>​​</span></span>)</span>(x)=<span><span>​<span>4−5x</span></span>​<span>​<span>3x+2</span></span><span>​​</span></span></span></span>

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What is a solution to the system? y = x^2 + 2x - 15 y – 4x = -12
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Answer:

  (x, y) = (-1, -16) or (3, 0)

Step-by-step explanation:

Perhaps you want to solve the system of equations ...

  • y = x^2 +2x -15
  • y -4x = -12

Substituting the first expression for y into the second equation gives ...

  x^2 +2x -15 -4x = -12

  x^2 -2x -3 = 0 . . . . . . . . add 12

  (x -3)(x +1) = 0 . . . . . . .  factor

Solutions are the values of x that make the factors zero: x = 3, x = -1.

The corresponding values of y are ...

  y = -12 +4x

  y = -12 +4{-1, 3} = -12 +{-4, 12} = {-16, 0}

The solutions to the system are ...

  (x, y) = (-1, -16) or (3, 0)

5 0
3 years ago
What is the slope of the line passing through the points (-3,4) and (4,-1)
Serhud [2]

Answer:

slope = - \frac{5}{7}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 4) and (x₂, y₂ ) = (4, - 1)

m = \frac{-1-4}{4+3} = - \frac{5}{7}

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3 years ago
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Step-by-step explanation:

5 0
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The amount of money left in Alma’s bank account is expressed by the linear equation y = -27x + 577, where x represents the numbe
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6 0
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A cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shif
omeli [17]

We have been given that a cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shift is 9 units down, and the period of the function is \frac{7\pi}{12}. The graph of the function does not show a phase shift. We are asked to write the equation of our function.

We know that general form a cosine function is y=A\cos(b(x-c))-d, where,

A = Amplitude,

\frac{2\pi}{b} = Period,

c = Horizontal shift,

d = Vertical shift.    

The equation of parent cosine function is y=\cos(x). Since function is reflected about x-axis, so our function will be y=-\cos(x).

Let us find the value of b.

\frac{2\pi}{b}=\frac{7\pi}{12}

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b=\frac{24}{7}

Upon substituting our given values in general cosine function, we will get:

f(x)=-11\cos(\frac{24}{7}x)-9

Therefore, our required function would be f(x)=-11\cos(\frac{24}{7}x)-9.

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