Which graph shows a system of equations with no solutions? On a coordinate plane, the graphs of 2 circles are shown. Both circle
s have a center at (0, 0). The smaller circle is within the larger circle and the smaller circle has a radius that is 2 units smaller than the larger circle. On a coordinate plane, a graph of a line and a parabola are shown. The line is horizontal to the x-axis at y = negative 5. The parabola opens up and its vertex on the line. On a coordinate plane, the graphs of 2 circles are shown. Both circles are in quadrant 1, and they intersect each other. On a coordinate plane, the graphs of 2 parabolas are shown. Both parabolas open up and they intersect each other at (0, 0). The first parabola has a vertex in quadrant 3 and the second parabola has a vertex in quadrant 4.
2 answers:
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Answer:
Step-by-step explanation:
The slope-intercept form is y = mx + b, where:
m = slope
b = y-intercept.
The slope (m) tells you the steepness of the line. It is the average rate of change which measures how the y-value changes for each one-unit change in the x-value. Hence, slope . So the given slope of 1/5 means that for every 1 unit change in the y-value, the x-value changes by 5 units (you go up 1 unit, and "run" 5 units to the right).
Next, the y-intercept is the point on the graph where it crosses the y-axis, and has the coordinates, (0, b). It is also the value of y when x = 0. Since you're given the y-intercept of -9, then that means that it is the y-coordinate of (0, <em>b</em>). So, it becomes (0, -9).
Now that we have our slope (<em>m </em>) = 1/5, and the y-intercept (<em>b </em>) = -9, we can write the equation of the line as:
(I'm also including a screenshot of the line where it shows the y-intercept of (0, -9) on the graph).
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