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Brilliant_brown [7]
3 years ago
10

Suppose the population of a town is 15,200 and is growing 2% each year. Write an equation to model the population growth. Predic

t the population after 10 years
Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
7 0

Answer:

The equation model is P = Po * e^rt

The population after 10 years = 18, 559 (most approximately)

Step-by-step explanation:

We use formula to find the population growth.

P = Po * e^rt

Where P is the total population after t years

Po is the initial population

r = rate of growth

t = time

e = 2.71 [Euler number]

The equation model is P = Po * e^rt

Now to find the population after 10 years, we have to plug in the given values in the formula.

Given:

Po = 15, 200, r = 2% = 2/100 = 0.02, and t = 10 years

P = 15,200*e^0.02(10)

P = 15,200*2.71^0.2

P = 15,200 *1.221

P = 18, 559

Therefore, the population after 10 years = 18, 559 (most approximately)

Dvinal [7]3 years ago
3 0
<span><span>1.       </span>So the current population of the town is 15 200 and is growing per year with 2%.
Find the population number after 10 years.
First, let’s find the value of 2%  in decimal form
=> 2/100
=> 0.02

Now, let’s try to solve
Population = 15 200 ( 1 + (0.02 x 10) )
Population = 15 200 ( 1 + 0.2 )
Population = 15 200 + 3040
Population =  18 240
Thus, in 10 years, the town’s population will increase to 18 240.



</span>



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Hi guys please help meee
Lisa [10]
<h3>Answer: 10</h3>

=======================================================

Explanation:

We'll start off converting each mixed number into an improper fraction.

The formula to use is A \frac{b}{c} = \frac{A*c+b}{c}

So,

A \frac{b}{c} = \frac{A*c+b}{c}\\\\2 \frac{1}{8} = \frac{2*8+1}{8}\\\\2 \frac{1}{8} = \frac{16+1}{8}\\\\2 \frac{1}{8} = \frac{17}{8}\\\\

And,

A \frac{b}{c} = \frac{A*c+b}{c}\\\\2 \frac{2}{3} = \frac{2*3+2}{3}\\\\2 \frac{2}{3} = \frac{6+2}{3}\\\\2 \frac{2}{3} = \frac{8}{3}\\\\

So the task of computing 2 \frac{1}{8} \times 2 \frac{2}{3} is exactly the same as computing \frac{17}{8} \times \frac{8}{3}

Notice how we have an 8 up top and an 8 down below. Those 8's cancel out and we're left with \frac{17}{3}. That fraction does not reduce any further.

The last step is to convert that improper fraction result to a mixed number.

\frac{17}{3} = \frac{15+2}{3}\\\\\frac{17}{3} = \frac{15}{3}+\frac{2}{3}\\\\\frac{17}{3} = 5+\frac{2}{3}\\\\\frac{17}{3} = 5 \frac{2}{3}\\\\

Or you could note that 17/3 leads to 5 remainder 2. The 5 is the whole part and the 2 forms the numerator of the fractional part 2/3.

The value is in A \frac{b}{c} form where

  • A = 5
  • b = 2
  • c = 3

Therefore, A+b+c = 5+2+3 = 10

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