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yuradex [85]
3 years ago
5

If Angle 6 is congruent to angle 10 and Angle 5 is congruent to angle 7, which describes all the lines that must be parallel? Li

nes r and s are crossed by lines t and u to form 16 angles. Clockwise from top left, at the intersection of r and t, the angles are 1, 2, 3, 4; at the intersection of s and t, 5, 6, 7, 8; at the intersection of u and s, 9, 10, 11, 12; at the intersection of u and r, 13, 14, 15, 16. Only lines r and s must be parallel. Only lines t and u must be parallel. Lines r and s and lines t and u must be parallel. Neither lines r and s nor lines t and u must be parallel.

Mathematics
2 answers:
mel-nik [20]3 years ago
8 0

Answer:

quick answer is the Third option-  Lines "r" and "s" and lines "t" and "u" must be parallel.

Nina [5.8K]3 years ago
7 0

Answer:

Third option: Lines "r" and "s" and lines "t" and "u" must be parallel.

Step-by-step explanation:

The missing figure is attached.

You need to remember that:

1- A Transversal is defined as a line that intersects two or more lines.

2- When a transversal cut two parallel lines, several angles are formed, which are grouped in pairs. Some of them are:

a. Vertical angles: are those pairs of angles that share the same vertex and are opposite to each other. These angles are congruent.

b. Corresponding angles: are those  pairs of non-adjacent angles located on the same side of the transversal and outside the parallel lines. They are congruent.

In this case, you can identify in the figure that:

 \angle 6 and \angle 10 are Corresponding angles.

\angle5 and \angle 7 are Vertical angles.

Therefore, based on the explained before, you can conclude that lines "r" and "s" and lines "t" and "u", must be parallel.

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If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?
Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

g(x)=4x^2-16

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:

\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)

Therefore, If we shift the red graph 9 units to the right and 1 down, our new function (let's call it h(x)) will be:

h(x)=4\left(x-9\right)^{2}-16-1 \\ \\ Simplifying: \\ \\ h(x)=4\left(x-9\right)^{2}-17

This graph is the blue graph below. Let's verify the transformation taking the vertex of the red graph:

(0,-16)

By translating the 9 units to the right and 1 down the vertex is also translated by the same rule, so:

New \ vertex: \\ \\ (0+9,-16-1) \\ \\ (9,-17)

<h2>Learn more:</h2>

Cubic function: brainly.com/question/13773618#

#LearnWithBrainly

5 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH THIS FUNCTION PROBLEM
ycow [4]

Answer:

Choose f(x) = 11x + 1

Step-by-step explanation:

Note that we will simply plug the value of 2 into the equation for February:

f(2) = 11(2) + 1 = 23

And plug the value of 6 into the equation for June:

f(6) = 11(6) + 1 = 67

Note how the points on the graph seem to match up with these values.  If we evaluate following the same style for each:

f(3) = 11(3) + 1 = 34

f(4) = 11(4) + 1 = 45

f(5) = 11(5) + 1 = 56

Note, these values seems to be very close in approximation to the graph points for each month.

The other three functions return values that are just to far away from what are represented in the graph.

Cheers.

8 0
4 years ago
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zavuch27 [327]
F(x) = g(x)
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I just substituted all the values in the domain to see which one would work. That's not really the quickest way but that's the only way I know

7 0
3 years ago
2. Carissa also has a sink that is shaped like a half-sphere. The sink has a volume of 3617 in3. One day, her sink clogged. She
sleet_krkn [62]

Answer:Yes, your answers are correct.

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We divide the volume of the sink, 2000π/3, by the volume of the cone:

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The diameter of the second conical cup is 8, so the radius is 4.  The volume then is:

V = 1/3π(4²)(8) = 128π/3

Dividing the volume of the sink, 2000π/3, by 128π/3:

2000π/3 ÷ 128π/3 = 2000π/3 × 3/128π = 6000π/384π = 15.625 ≈ 16

Step-by-step explanation:

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