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yuradex [85]
3 years ago
5

If Angle 6 is congruent to angle 10 and Angle 5 is congruent to angle 7, which describes all the lines that must be parallel? Li

nes r and s are crossed by lines t and u to form 16 angles. Clockwise from top left, at the intersection of r and t, the angles are 1, 2, 3, 4; at the intersection of s and t, 5, 6, 7, 8; at the intersection of u and s, 9, 10, 11, 12; at the intersection of u and r, 13, 14, 15, 16. Only lines r and s must be parallel. Only lines t and u must be parallel. Lines r and s and lines t and u must be parallel. Neither lines r and s nor lines t and u must be parallel.

Mathematics
2 answers:
mel-nik [20]3 years ago
8 0

Answer:

quick answer is the Third option-  Lines "r" and "s" and lines "t" and "u" must be parallel.

Nina [5.8K]3 years ago
7 0

Answer:

Third option: Lines "r" and "s" and lines "t" and "u" must be parallel.

Step-by-step explanation:

The missing figure is attached.

You need to remember that:

1- A Transversal is defined as a line that intersects two or more lines.

2- When a transversal cut two parallel lines, several angles are formed, which are grouped in pairs. Some of them are:

a. Vertical angles: are those pairs of angles that share the same vertex and are opposite to each other. These angles are congruent.

b. Corresponding angles: are those  pairs of non-adjacent angles located on the same side of the transversal and outside the parallel lines. They are congruent.

In this case, you can identify in the figure that:

 \angle 6 and \angle 10 are Corresponding angles.

\angle5 and \angle 7 are Vertical angles.

Therefore, based on the explained before, you can conclude that lines "r" and "s" and lines "t" and "u", must be parallel.

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How much of the circle is shaded? Write your answer as a fraction in simplest form. 1/3 and 1/7
Ludmilka [50]

Answer:

11/21

Step-by-step explanation:

1/3=7/21

1/7=3/21

(7+3)/21=10/21

21/21-10/21=11/21

Thus 11/21 of the circle is shaded.

6 0
3 years ago
Marci works at a hardware store. One cash flow estimate for their power tools department is $56,700, and the probability assessm
worty [1.4K]

Answer:

The given data represents, the 30% of TOTAL CASH INFLOW = $56,700 and it is in the power tools department.

Step-by-step explanation:

Here, according to the question:

The estimated cash flow of POWER TOOLS department  =  $56,700

Also, the probability assessment = 30%

So, the given 30% determines the percentage of cash flow in POWER TOOLS DEPARTMENT in comparison to the TOTAL CASH FLOW.

Here, Maci is trying to find out the portion of the cash inflow in power tools department with respect to the cash flow of other departments in the hardware store.

The given data represents, the 30% of TOTAL CASH INFLOW = $56,700 and it is in the power tools department.

7 0
3 years ago
Solve for x using the Quadratic Formula: x2 + 4x + 4 = 0<br> -b + Vb2 - 4ac<br> x=<br> 2a
Irina18 [472]

Answer:

x = -2.

Step-by-step explanation:

In this case, a is 1, b is 4 and c is 4.

-4 plus or minus the square root of 4^2 - 4 * 1 * 4 divided by 2 * 1 = -4 plus or minus the square root of 16 - 16 / 2 = -4 plus or minus the square root of 0 / 2 = -4 / 2 = -2.

x = -2.

Hope this helps!

8 0
3 years ago
A packet of candles and box of matches cost #420. The candles cost 20 times as much as the matches
olga55 [171]

Answer:

candles = $400

matches = $20

Step-by-step explanation:

Let cost of candles = $c

Let cost of matches = $m

c = 20 m (20 times m)

c + m = 420

20m + m = 420

21 m = 420

m = 20

c = 20 (20) = 400

6 0
3 years ago
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
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