Hopes this helps:
Answer: C. x < -1
Y= (x-2)² + 5. We can write it as : y-5 = (x-2)². The general equation of a quadratic function is :
(y-k) = a(x-h)², where h and k are the vertex of the parabola and a, the coefficient which determines whether the parabola opens upward or downward.
So, y-5 = (x-2)²
Having said that we can say that the VERTEX( 2,5) and since a=1 (a>0) the parabola is open upward OR it passes by a MINIMUM (Then the vertex is minimum)
The domain (x- value) is all Real { x|x = -∞ to x=+∞}
The Range (y-value) is all y ≥ 5
Hey there!
To start, whenever you are performing (f+g)(x), this means that you are to add the functions f(x) and g(x) together.
In this case, f(x) is equal to 5x^3-2 and g(x) is equal to 2x+1.
Because you are adding the two expressions as according (f+g)(x), you should set up this expression:
(5x^3-2)(2x+1)
Now, combine your like terms (terms of the same variables that are all raised to the same power):
(5x^3-2)(2x+1)
=5x^3+2x-1
Therefore, (f+g)(x)=5x^3+2x-1
Hope this helps and I hope you have a marvelous day! :)
A and b both have to be 8 so the answer is 8