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3 years ago

Will give brainliest please help

Mathematics

1 answer:

nataly862011 [7]3 years ago

8 0

Answer:

The answer is B

Step-by-step explanation:

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The population of a city decreases by 1% per year. If this year's population is 381,000, what will next year's population be, to

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Think its 377,190 population

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3 years ago

A new surgical procedure is said to be successful 60% of the time. Suppose the operation is performed five times and the results

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Answer:

0.07776, 0.3456,0.08704

Step-by-step explanation:

Given that a new surgical procedure is said to be successful 60% of the time

Let X be the no of successes

Then X has only two outcomes and each trial is independent of the other

Hence X is binomial with p = prob of success in a single trial = 0.60

n = Number of operations performed = 5

Prob that

a) all five operations are successful =

$P(X=5)\\= (0.6)^5\\=0.07776$

(b) exactly three are successful

= $P(X=3) = 5C3 (0.6)^3(0.4)^2\\= 0.3456$

$==P(X$

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3 years ago

The temperature in Virginia fell

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Answer:

Step-by-step explanation:

you add the absolute values

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3 years ago

Test the claim below about the mean of the differences for a population of paired data at the level of significance α Assume the

Evgen [1.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is F

$t = 1.17$

$t_ {\alpha , df} =t_ {0.10 , 8} = 1.86$

Since the test statistics is outside the rejection region , we fail to reject the null hypothesis ,There is no statistically significant evidence to reject the claim

Step-by-step explanation:

From the question we are told that

The claim is $\mu = 0$

Hence

The null hypothesis is $H_o : \mu = 0$

The alternative is $H_a : \mu \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= d - \mu_d }{ \frac{s_d}{ \sqrt{n} } }$

=> $t = \frac{3.5 -0 }{ \frac{8.94}{ \sqrt{9} } }$

=> $t = 1.17$

Generally the degree of freedom is mathematically represented as

$df = n- 1$

$df = 9 - 1$

$df = 8$

From the student t-distribution table the critical value of $\alpha$ at a degree of freedom of 8 is

$t_ {\alpha , df} =t_ {0.10 , 8} = 1.86$

Since the $t_ {\alpha , df}$ is outside the rejection region , we fail to reject the null hypothesis ,There is no sufficient evidence to reject the claim

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4 years ago

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