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3 years ago

A square flower garden has an area of 144 square feet. What is the length of one side of the garden?

Mathematics

2 answers:

Damm [24]3 years ago

6 0

The answer is 12 feet because 144 squared is 12.
Hope this helps

ICE Princess25 [194]3 years ago

4 0

Since it is a square

area = S^2

144 = S^2

S = sqrt(144)

S =12

length = 12 feet

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Given the function f(x) = 2|x + 6| – 4, for what values of x is f(x) = 6?

lara [203]

Answer:

x = -1 , - 11,

Step-by-step explanation:

| x | = x

|- x | = x

f(x) = 2 | x + 6 | - 4

x = - 1 , f( - 1) = 2 | - 1 + 6 | - 4 = 2 | 5 | - 4 = 10 - 4 = 6 , True

x = 1 , f( 1 ) = 2 | 1 + 6 | - 4 = 2 | 7 | - 4 = 14 - 4 = 10 , False

x = 11, f( 11 ) = 2 | 11 + 6 | - 4 = 2 | 17 | - 4 = 34 - 4 = 30 , False

x = - 11, f( - 11) = 2 | -11 + 6 | - 4 = 2 | - 5 | - 4 = 10 - 4 = 6 , True

x = 14 , f( 14 ) = 2 | 14 + 6 | - 4 = 2 | 20 | - 4 = 40 - 4 = 36 , False

x = -14 , f( - 14 ) = 2 | - 14 + 6 | - 4 = 2 | - 8 | - 4 = 16 - 4 = 12 , False

x = - 26 , f( - 26) = 2 | -26 + 6 | - 4 = 2 | -20 | - 4 = 40 - 4 = 36 , False

x = 26, f( 26 ) = 2 | 26 + 6 | - 4 = 2 | 32 | - 4 = 64 - 4 = 60 , False

Given f ( x ) = 6

f( x ) = 2 | x + 6 | - 4

6 = 2 | x + 6 | - 4

6 + 4 = 2 | x + 6| - 4 + 4 [ adding 4 to both sides ]

10 = 2 | x + 6 | + 0

5 = | x + 6 | [ dividing both sides by 2 ]

$- 5 =\ ( x+ 6) \ = 5\\\\$ $[ \ | x | = a\ => \ -a \ = x \ = a \ ]$

$- 5 - 6 = \ x + 6 - 6 \ = \ 5 - 6\\$ $[ \ subtracting \ by \ 6 \ ]$

$-11 = \ x \ = - 1$

3 0

3 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

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3 years ago

Write the expression (−2)·(−2)·7·7·7·7·7 using exponents.

NeTakaya

Answer: $(-2)^{2}*7^{5}$

Step-by-step explanation:

You have to group all of the same one's together and however many there is, you add that number as the exponent.

There were 2 "(-2)" so that became $(-2)^{2}$ , and there were 5 "7" so that became $7^{5}$ . You keep the symbol and put it together which became $(-2)^{2}*7^{5}$

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3 years ago

The tables below represent the profits earned by a merchandiser from four new consignments of t-shirts. Each consignment contain

steposvetlana [31]

The first consignment shows no association between the t-shirt size and the profit.

In the second consignment, the bigger the t-shirt size, the smaller the profit. There is an inverse relationship between the two variables.

In the third and fourth consignment, the bigger the size, the larger the profit. There is a direct relationship between the two variables.

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If you help me answer this question i will give you brainiest!!

coldgirl [10]

Angle BDC is given as 38° but not drawn in the figure. Amateurs.

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We won't bother subtracting because we're really after

angle ABD = 180° - DBC = 134°

Now we have a Law of Cosines situation,

AD² = AB² + BD² - 2(AB)(BD) cos ABD

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AD ≈ 31.61 m

Answer: 31.6 m

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3 years ago

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