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Otrada [13]
2 years ago
8

These 20 ages of children on a school bus are in order from least to greatest. 5, 5, 5, 6, 6, 7, 7, 8, 9, 10, 10, 11, 12, 12, 12

, 14, 14, 14, 15, 17
Find the

first quartile

third quartile


Find the interquartile range:
Mathematics
1 answer:
umka2103 [35]2 years ago
8 0

Answer:

the interquartile range is the Q3-Q1 where Q3 is 75th percentile and Q1 is the 25th percentile.

so the total count is 20 so 25 percentile is 25% of 20 =5 and 75th percentile is 75% of 20 = 15 and since the number are already arranged in order we just pick the 15th number-5th number   thus, our answer is

                              12-6 = 6

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Can someone please help with this? I'll give brainliest. I don't understand this... or the explanation it gives... the page befo
tresset_1 [31]

Step-by-step explanation:

Hello!
I'd love to help you learn.
I see the formula attached is 4*(\frac{1}{2})^{x} =-2^{x}-1\\

This problem is explaining you to graph, since algebraically it's a little more harder to try and find the solution.

Since they're both equal to each other, we can assign a variable like y, so we can make them into two individual lines.

You can use your scientific calculator to graph lines like this, or otherwise there are online sources (Desmos helps alot!) which can graph two equations as so.

Now that we have the corresponding system of equations, we can graph both.

y=4*(\frac{1}{2})^x\\ y=-2^x-1
Let's graph them on Desmos on the same plane. The answers are attached. Red is the first equation, blue is the second.

What determines the solutions of a system of equations?

-No solution: the two lines will never intersect/does not intersect ever, which means that there are no set point where it satisfies both equations.

-One solution: the two lines intersect once and only once, meaning that there is that one set point where the x and y values both satisfy both equations.

-Multiple solutions: the two lines will intersect each other multiple times, meaning there are multiple set points where the x and y values satisfy both equations. You usually will not have to worry about these problem sets.

-Infinite solutions: the two lines are both the same line, which means every x and y value will satisfy both equations.

Looking at the solution attached, we can see that there are no places where a system of equations intersect, therefore ruling it that they have no solution.

And to answer your last question, an asymptote is a imaginary line in which a equation can approach closely and closely, but will never touch that imaginary line. Think of a line at y=\frac{1}{x}. When you graph it, you can see that the two lines never ever EVER intersect the y-axis, or x=0; giving that x=0 as a vertical asymptote.

5 0
2 years ago
Negation "If it rains then I take an umbrella."
Ber [7]
This means that if it’s raining take an umbrella and go thru it regardless in life
8 0
2 years ago
Use the Pythagorean Theorem to determine which of the following give the measures of the legs and hypotenuse of a right triangle
kakasveta [241]

The Pythagorean theorem states that the square of the hypotenuse is equal to  the sum of the squares of the legs:

c^2=a^2+b^2.

The hypotenuse is the side with the greatest length.

Check all options:

1. c=5, a=3, b=4:

5^2=25,\\3^2+4^2=9+16=25,\\5^2=3^2+4^2 true.

2. c=14, a=4, b=11:

14^2=196,\\4^2+11^2=16+121=137,\\14^2\neq 4^2+11^2 false.

3. c=17, a=9, b=14:

17^2=289,\\9^2+14^2=81+196=277,\\17^2\neq 9^2+14^2 false.

4. c=16, a=8, b=14:

16^2=256,\\8^2+14^2=64+196=260,\\16^2\neq 8^2+14^2 false.

5. c=17, a=8, b=15:

17^2=289,\\8^2+15^2=64+225=289,\\17^2=8^2+15^2 true.

Answer: correct options are A and E.

4 0
2 years ago
Read 2 more answers
Hi can you help me ? what is 0.07 ? ​
riadik2000 [5.3K]

Answer:

I think it's zero point zero seven.

Step-by-step explanation:

6 0
2 years ago
Solve p=10a+3b for a
Gre4nikov [31]

Answer:

a = (p - 3b)/10

Step-by-step explanation:

Isolate the variable, a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS (Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction).

p = 10a + 3b

First, subtract 3b from both sides.

p (-3b) = 10a + 3b (-3b)

p - 3b = 10a

Next, isolate the a. Divide 10 from both sides.

(p - 3b)/10 = (10a)/10

(p - 3b)/10 = a

a = (p - 3b)/10 is your answer.

~

5 0
3 years ago
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