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Sav [38]
3 years ago
15

five years ago a man was seven times as old as his son. five years hence the gather would be three times as old as his son. find

their present ages
Mathematics
1 answer:
babymother [125]3 years ago
5 0
Father = x
son = y
x-5 = 7(y-5)
x +5 = 3(y+5) solve the system

x-5 = 7y-35
x+5 = 3y +15

x-5 = 7y-35
-x-5 = -3y -15
-10 = 4y -50
+50 +50
40 = 4y
10 = y

Solve for X
x+5 = 3(10) + 15
x+5 = 45
x = 40

The father is 40yrs old and the son is 10yrs old.
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<span>1. Let t = time in years, with t = 0 representing the year 2005. Let f(t) = the number of students enrolled at the private school and g(t) = the number of students enrolled at the public school. Create the two functions to represent the situation.

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