five years ago a man was seven times as old as his son. five years hence the gather would be three times as old as his son. find
their present ages
1 answer:
Father = x
son = y
x-5 = 7(y-5)
x +5 = 3(y+5) solve the system
x-5 = 7y-35
x+5 = 3y +15
x-5 = 7y-35
-x-5 = -3y -15
-10 = 4y -50
+50 +50
40 = 4y
10 = y
Solve for X
x+5 = 3(10) + 15
x+5 = 45
x = 40
The father is 40yrs old and the son is 10yrs old.
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0.35 = 35/100.
Can be simplified. Divide by 5.
= 7/20
The answer is 1.5 i think
To find one tenth of 119.9 just divide 119.9 by 10
Answer:
15.38461538461538
Step-by-step explanation:
X=9 this is the answer for question 19
