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Sav [38]
3 years ago
15

five years ago a man was seven times as old as his son. five years hence the gather would be three times as old as his son. find

their present ages
Mathematics
1 answer:
babymother [125]3 years ago
5 0
Father = x
son = y
x-5 = 7(y-5)
x +5 = 3(y+5) solve the system

x-5 = 7y-35
x+5 = 3y +15

x-5 = 7y-35
-x-5 = -3y -15
-10 = 4y -50
+50 +50
40 = 4y
10 = y

Solve for X
x+5 = 3(10) + 15
x+5 = 45
x = 40

The father is 40yrs old and the son is 10yrs old.
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Answer:

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Step-by-step explanation:

-16+x=-15

-16+x+16=-15+16   Add the terms to both sides of the equation.

After that you simplify.

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EastWind [94]

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7. 163 pizzas

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Step-by-step explanation:

7. 1,956 divided by 12 equals 163

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2 years ago
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I’ll give brainliest to whoever answers thiss
andrey2020 [161]

Answer:

21.25

Step-by-step explanation:

diagonal is 21.25

the area is 216.75

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6 0
2 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
Need help on this please
Akimi4 [234]
Question 10
30-2=28

28*2= 56
56*2= 112
120*2= 240

240+112=352.

Area = 352 square feet
Question 11
Volume = pi*r*r*h
=3.142*2.5*2.5*0.5
= 9.817
From the choices the answer is
D. 9.8 cubic ft
7 0
3 years ago
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