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victus00 [196]
3 years ago
5

Can someone help me with this problem

Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0
-13/24 because u have to multiply to get the same denominator which would end up being -15/24 and 2/24 add that to get -13/24
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Anne and Dawn share £120 in the ratio 5:3. How much did Dawn receive?
GrogVix [38]

Answer:

45 !!

Step-by-step explanation:

Anne = 5x

Dawn= 3x

Amount = 120

5x + 3x = 120

8x = 120

x= 120/8 = 15

Anne = 5x = 15 x 5 = 75

Dawn= 3x = 15 x 3 = 45

I hope im right!!

8 0
3 years ago
11th grade Algebra 2, please help.<br> If g(t) = 2/(t + 3) then g( blank) - 2/(4a + 3)
Helen [10]

Answer:

blank = 4a

Step-by-step explanation:

If g(t) = 2/(t + 3)

then g(4a) = 2/(4a+3)

5 0
3 years ago
A 50% sucrose solution lost 255 mL by evaporation. After evaporation what is the sucrose concentration in the remaining 300 mL?
Len [333]

Answer: 92.50%

From the given problem, we can say that the total volume of the concentration is:

255\text{ mL}+300\text{ mL}=555\text{ mL}

The initial volume of the solution is 555 mL. After the evaporation, the 50% sucrose solution lost 255 mL.

To find the concentration of the remaining 300 mL, we will use the following formula:

C_1V_1=C_2V_2

Where:

C₁ = initial concentration

C₂ = final concentration

V₁ = initial volume

V₂ = final volume

From the given, we know that:

C₁ = 50% = 0.50

C₂ = ?

V₁ = 555 mL

V₂ = 300 mL

Substitute these to the formula and we will get:

\begin{gathered} C_{1}V_{1}=C_{2}V_{2} \\ (0.50)(555)=C_2(300) \\ C_2=\frac{(0.50)(555)}{(300)} \\ C_2=0.925=92.50\% \end{gathered}

Therefore, we can say that the sucrose concentration in the remaining 300mL is 92.50%

5 0
2 years ago
Someone seriously help me im tired of the links
shutvik [7]
The answer is y=$10x+25
4 0
3 years ago
PLS HELP ASAP I WILL GIVE BRAINERLIST PLUS 10 POINTS
Tresset [83]
It’s the 3rd answer choice
6 0
3 years ago
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