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3 years ago

5

the vertices of a parallelogram are (0,0),(5,0),(8,2),(3,2) what are the coordinates if the parallelogram was reflected in the y

axis.

1 answer:

just olya [345]3 years ago

7 0

(0,0) (-3,2) (-5,0) (-8,2)

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4 lbs of tomato’s cost $14 complete the double number line so that it shows how much it will cost for up to 8 lbs of tomato’s

faust18 [17]

Answer:

the answer is 28$ because since the lbs get doubled so ypu also have to double the cost

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3 years ago

Solve the following equation:<br> V= 2(ab+bc+ca), for a

Nadya [2.5K]

V = 2ab + 2ca + 2bc

2ab + 2ca = V - 2bc

2a * b + c = V - 2bc

Answer: a = v - 2bc / 2 * b + c

Hope that helps!!!!! : )

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3 years ago

Solve the system of equations

dlinn [17]

Answer:

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Step-by-step explanation:

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3 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

3 years ago

In a geometric sequence, if a3 = ‒5 and a6 = 40, determine a1, r, and an. Then write the first three terms of the sequence.

Tresset [83]

$a_4=ra_3$
$a_5=ra_4=r^2a_3$
$a_6=ra_5=r^3a_3$

$40=-5r^3\implies r^3=-8\implies r=-2$

$a_3=ra_2=r^2a_1$

$-5=(-2)^2a_1\implies a_1=-\dfrac54$

You know the first and third terms, $a_1$ and $a_3$ , so you just need to find the second term $a_2$ :

$a_2=ra_1\implies a_2=-2\left(-\dfrac54\right)=\dfrac52$

7 0

3 years ago