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Julli [10]
3 years ago
5

the vertices of a parallelogram are (0,0),(5,0),(8,2),(3,2) what are the coordinates if the parallelogram was reflected in the y

axis.
Mathematics
1 answer:
just olya [345]3 years ago
7 0
(0,0) (-3,2) (-5,0) (-8,2)
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PLS ANSWER !!!! <br><br> what is the formula when finding the slope given in two ordered pairs
Katarina [22]

Answer: Since you already know that the ordered pair is in the format of (x, y), then you can label one of the ordered pairs as 1 and kind of distribute it to get 1(x, y) = (x-sub1, y-sub1). Then just use the slope formula (y2-y1)/(x2-x1).

Step-by-step explanation:

5 0
4 years ago
12x5 – 10x2 + x – 45
qaws [65]
(a)
12x  ^{5}    - 10x ^{2}  + x - 45
(b)we have 4 terms in this expression.
(c)+12 is the leading coefficient in
12x ^{5}

(d) constant is -45
6 0
3 years ago
-27 - x = -51<br> ................
Katarina [22]

Answer:

24

Step-by-step explanation:

-27 - x = -51

+27     +27

-x = -24

x = 24

6 0
3 years ago
HI I need help please <br> Its in the pictures
Brut [27]
1.

r=32\,\text{units}\\\\&#10;A=\pi\cdot r^2=\pi\cdot32^2=1024\pi\,\,\text{units}^2

Answer D.

2.
From secant theorem, we know, that:

|AE|\cdot|BE|=|DE|\cdot|CE|

and from picture:

|BE|=x+1\\\\|CE|=x+4\\\\|AE|=11+x+1=x+12\\\\|DE|=1+x+4=x+5

So we can calculate:

|AE|\cdot|BE|=|DE|\cdot|CE|\\\\(x+12)\cdot(x+1)=(x+5)\cdot(x+4)\\\\&#10;x^2+12x+x+12=x^2+5x+4x+20\\\\&#10;x^2+13x+12=x^2+9x+20\quad|-x^2\\\\13x+12=9x+20\quad|-9x\\\\4x+12=20\quad|-12\\\\4x=8\quad|:4\\\\\boxed{x=2}
8 0
3 years ago
Write the equation of the line that passes through the given point and is parallel to the given line.
romanna [79]

<u>(Note: this answer is assuming that the equation has to be put in slope-intercept format.)</u>

Answer:

y = \frac{1}{2} x - \frac{5}{2}

Step-by-step explanation:

1) Let's use the point-slope formula to determine what the answer would be. To do that though, we would need two things: the slope and a point that the equation would cross through. We already have the point it would cross through, (-3,-4), based on the given information. So, in the next step, let's find the slope.

2) We know that the slope has to be parallel to the given line, y = \frac{1}{2}x - 8. Remember that slopes that are parallel have the same slope - so, let's simply take the slope from the given equation. Since it's already in slope-intercept form, we know that the slope then must be \frac{1}{2}.

3) Finally, let's put the slope we found and the x and y values from (-3, -4) into the point-slope formula and solve:

(y- (-4))  = \frac{1}{2} (x - (-3))\\y + 4 = \frac{1}{2} (x + 3))\\y + 4 = \frac{1}{2}x+ \frac{3}{2} \\y = \frac{1}{2}x + \frac{3}{2} - 4\\y =  \frac{1}{2}x + \frac{3}{2} - \frac{8}{2} \\y = \frac{1}{2}x - \frac{5}{2}

Therefore, y = \frac{1}{2}x - \frac{5}{2} is our answer. If you have any questions, please do not hesitate to ask!

3 0
3 years ago
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