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3 years ago

What is the y intercept

Mathematics

1 answer:

kari74 [83]3 years ago

3 0

Answer:

There is not a y-intercept

Step-by-step explanation:

The line does not cross y=0

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Math question, please help

vagabundo [1.1K]

The Answer is
$3 \times {10}^{8}$
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3 years ago

A jar contains 10 red marbles and 20 blue marbles. if one red marble is selected and then placed back into the jar, what is the

Serggg [28]

You have a 30% chance of getting a blue marble. <span />

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3 years ago

220 students were asked if they liked chocolate or vanilla ice cream. 140 said they liked chocolate and 120 said they liked vani

Flura [38]

Answer: D. 40

Step-by-step explanation:

Given: Number of students liked vanilla or chocolate ice cream = $n(V\cup C)=220$

Number of students liked chocolate = $n(C)=140$

Number of students liked vanilla= $n(V)=120$

Now, Number of students liked vanilla and chocolate ice cream is given by :-

$n(V\cap C)=n(C)+n(V)-n(V\cup C)\\\\\Rightarrown(V\cap C)=140+120-220\\\\\Rightarrown(V\cap C)=260-220\\\\\Rightarrown(V\cap C)=40$

Number of students liked vanilla and chocolate ice cream= 40

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4 years ago

Which of the following is not a 3-D shape? A. quadrilateral B. cube C. sphere D. prism

Maslowich

Answer:

Step-by-step explanation:

A quadrilateral is simply a shape with 4 sides, therefore it does not HAVE to be 3-D.

4 0

3 years ago

Read 2 more answers

An average computer mouse inspector can inspect 50 mice per hour. The 48 computer mice inspectors at a particular factory can on

Ronch [10]

Answer: C. Yes, because -2.77 falls in the critical region .

Step-by-step explanation:

Let $\mu$ be the population mean .

As per given , we have

$H_0:\mu=50\\\\ H_a: \mu$

Since the alternative hypothesis is left-tailed and population standard deviation is not given , so we need to perform a left-tailed t-test.

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

Also, it is given that ,

n= 48

$\overline{x}=46$

s= 10

$t=\dfrac{46-50}{\dfrac{10}{\sqrt{48}}}=\dfrac{-4}{\dfrac{10}{6.93}}\\\\=\dfrac{-4}{1.443}\approx-2.77$

Degree of freedom = df = n-1= 47

Using t-distribution , we have

Critical value = $t_{\alpha,df}=t_{0.025,47}=2.0117$

Since, the absolute t-value (|-2.77|=2.77) is greater than the critical value.

So , we reject the null hypothesis.

i.e. -2.77 falls in the critical region.

[Critical region is the region of values that associates with the rejection of the null hypothesis at a given probability level.]

Conclusion : We have sufficient evidence to support the claim that these inspectors are slower than average.

Hence, the correct answer is C. Yes, because -2.77 falls in the critical region

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4 years ago