If (y-1) is a factor of f(y), f(y)=0 when y=1. So if you find that f(1)=0, then (y-1) is a factor of f(y).
f(y)=y^3-9y^2+10y+5
f(1)=1-9+10+5=7
Since f(1)=7, (y-1) is not a factor.
Answer:
if f(x) = 3x+4, the rate of change is 4.
if f(x) = 2x+7, the rate of change is 2.
Step-by-step explanation:
We know that the average rate of change over the interval x=0 to x=8 is:
(f(x2) - f(x1))/x2-x1
Where:
x2 = 8
x1 = 0
if f(x) = 3x+4
so f(8)=3(8)+4 = 28
f(0)=3(0)+4 = 4
Then: (f(x2) - f(x1))/x2-x1 = (28 - 4)/8-0 = 24/8 = 3
On the other hand, if f(x) = 2x+7
f(8) = 2(8)+7 = 23
f(0) = 2(0)+7 = 7
Then: (f(x2) - f(x1))/x2-x1 = Then: 23 - 7/8-0 = 16/8 = 2
Answer:
d
Step-by-step explanation:
it's the answer because it's the answer and it makes sense because I know it does
To find the area of a cone you do A=πr(r+
Which give you the answer of 151.58
