All categories

3 years ago

11. If Sally

Mathematics

1 answer:

Delvig [45]3 years ago

3 0

Answer:

0.2

Step-by-step explanation:

Multiply 4/5 and 1/4: Decimal form

.8 • .25

You might be interested in

Sarah went to the candy store to buy treats for her halloween party. She came out with 11 pounds of candy. She bought m&m's

Papessa [141]

Answer:

5lb of m&mns and 6lb of raisinets

Step-by-step explanation:

5lb x 2$ = $10

6lb x 1.5 = $9

8 0

3 years ago

Read the word problem below.

salantis [7]

Answer:

1 3/5 miles/hr

Step-by-step explanation:

Let C be the speed of the current

Let D be the distance between Chan's house and the park

We know that Distance, D, is = Speed x Time

-----

Chan's speed going upstream is (8 - C)mph.

That gives us:

D = (8-C)(3 hr)

Chan's speed going downstream is (8+C)mph

So we have:

D = (8+C)(2 hr)

We know that the d is the same for these two equations, so:

(8-C)(3 hr) = (8+C)(2 hr)

24 - 3C = 16 + 2C

5C = 8

C = (8/5) or 1 3/5 mph

5 0

1 year ago

Read 2 more answers

-4x^4 - 3x^3 - 29x^2 - 114 where x= -4

tatiyna

Answer: -1410

Step-by-step explanation:

Let's start by subbing in -4 for x

$-4x^4 - 3x^3 - 29x^2 - 114\\-4(-4)^4-3(-4)^3-29(-4)^2-114$

Now we can solve

$-4(256)-3(-64)-29(16)-114\\-1024--192-464-114\\-832-464-114\\-1296-114\\-1410$

5 0

3 years ago

Read 2 more answers

The senior classes at High School A and High School B planned separate trips to Lake Compounce. The senior class at High School

storchak [24]

Answer:

Number of students in vans =15 and bus =46

Step-by-step explanation:

use variables for the vans and buses

let x= vans and y=buses

Now solve the 2 equations simultaneously

remember to number your equations

6x+7y=412..........1

6x+9y=504.........2

make x the subject of one equation

and label it equation 3

6x=412—7y

$x = \frac{206}{3} - \frac{7y}{6} .............3$

subs 3 into 2

$6( \frac{206}{3} - \frac{7y}{6} ) + 9y = 504$

$412 - 7y + 9y = 504$

$- 7y + 9y = 504 - 412$

$2y = 92$

$y = 46...................4$

subs 4 into 1

$6x + 7(46) = 412$

$6x + 322 = 412$

$6x = 412 - 322$

$6x = 90$

$x = 15$

Therefore there are 15 students in each van and 46 students in each bus.

3 0

2 years ago

assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra

Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = Number of adults who use their smartphones

The above situation can be represented through the binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......$

where, n = number of trials (samples) taken = 15 adult smartphones

r = number of success = at least 4

p = probability of success which in our question is the % of adults

who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}$

= $1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})$

= 0.1773

3 0

3 years ago