Answer: See attached
Step-by-step explanation:
[] Since the inequality uses greater than (>) and <em>not</em> greater than or equal to (≥), the line will be dashed.
[] The inequality is greater than (>) so we will shade above the line as values "above" are greater.
This question may be trick question xD haha.
Anyways, a right triangle is a triangle with a right angle (90 degrees). In your picture, that triangle is a right triangle, but the sides could be a bit slanted. Please take a picture from top view, so I can see it properly.
The triangle's length does not matter in this case. As long as it has a right angle, it's a right triangle.
Answer:
Step-by-step explanation:
In general, remember that the converse of
is
, therefore in this case 
so
A) 20+10h
You know that you have 20 inches to start with, then it will grow 2h four times, or 8h total. Then it will grow h 2 times, or 2h. You add the 20, 8h, and 2h, to get 20+10h.
Hope this helps!
Answer:

Step-by-step explanation:
step 1
Find the measure of the arc DC
we know that
The inscribed angle measures half of the arc comprising
![m\angle DBC=\frac{1}{2}[arc\ DC]](https://tex.z-dn.net/?f=m%5Cangle%20DBC%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20DC%5D)
substitute the values
![60\°=\frac{1}{2}[arc\ DC]](https://tex.z-dn.net/?f=60%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20DC%5D)


step 2
Find the measure of arc BC
we know that
----> because the diameter BD divide the circle into two equal parts
step 3
Find the measure of angle BDC
we know that
The inscribed angle measures half of the arc comprising
![m\angle BDC=\frac{1}{2}[arc\ BC]](https://tex.z-dn.net/?f=m%5Cangle%20BDC%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20BC%5D)
substitute the values
![m\angle BDC=\frac{1}{2}[60\°]](https://tex.z-dn.net/?f=m%5Cangle%20BDC%3D%5Cfrac%7B1%7D%7B2%7D%5B60%5C%C2%B0%5D)

therefore
The triangle DBC is a right triangle ---> 60°-30°-90°
step 4
Find the measure of BC
we know that
In the right triangle DBC


substitute the values
