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3 years ago

Please help me on this one.

Mathematics

2 answers:

EleoNora [17]3 years ago

7 0

3(j+4)-9=9
3j + 12 -9 =9
3j +3 =9
3j =6
j=2

gayaneshka [121]3 years ago

5 0

Ignore the top hope this helps

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Multiply.<br> (x-6)(4x + 3)

d1i1m1o1n [39]

Answer:

Fully simplified it equals 4x^2 -21x -18

Explanation:

-You need to distribute the x to all of the terms in the second binomial and you also need to distribute -6 to all the terms in the second binommial giving you 4x^2 +3x - 24 -18

-You combine like terms to simplify and your answer is 4x^2 -21x -18

7 0

3 years ago

What is the solution to the system of equations g(x)=-2x-3 f(x)=x+1-4

Ainat [17]

Answer: Not positive that this is right but here is what I got.

Step-by-step explanation:

Set up the composite result function.

g ( f )( x )

Evaluate g(f)(x) by substituting in the value f into g

(2x - 3) + 1

Add -3 and 1

g ( 2 x − 3 ) = 2 x − 2

4 0

3 years ago

This box plot represents the weights of several students in sixth grade. Use the shape of the box plot to describe the data set.

Levart [38]

Answer:

I think it should be A, D, E, G

Step-by-step explanation:

3 0

3 years ago

PLZ HELP ASAP! ILL MARK BRAINLEST!

Sav [38]

Question 1.) Factor completely $12x^{4}+ 6x^{3}+18x^{2}$

Since $6$ divides all the three terms of the equation, so we take $6$ common out from the equation.

i.e., $6(2x^{4}+ 1x^{3}+3x^{2})$

Now, since $x^{2}$ divides all the three terms of the equation, so we take $x^{2}$ common out from the equation.

i.e., $6x^{2}(2x^{2}+ 1x+3)$

Now, this cannot be factored further as $2x^{2}+ 1x+3$ is a quadratic equation and taking out discriminant of it is:

$D = (1)^2 - 4(2)(3)\\ \ \ = 1- 24\\ \ \ = -23$

Since, the discriminant is less than zero. Therefore, the factored form of the given equation : $12x^{4}+ 6x^{3}+18x^{2}$ is : $6x^{2}(2x^{2}+ 1x+3)$

Question 2.) $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$

Since $7$ divides all the three terms of the equation, so we take $7$ common out from the equation.

i.e., $7(x^{3}y+ 2x^{2} y^{3} - x^{2}y^{2})$

Now, since $x^{2}y$ divides all the three terms of the equation, so we take $x^{2}y$ common out from the equation.

i.e., $7x^{2}y(x+ 2y^{2} - y)$

Therefore, the factored form of the given equation : $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$ is : $7x^{2}y(x+ 2y^{2} - y)$

Question 3.) What is the Greatest Common Factor of $x^{6}$ and $x^{3}$ ?

The Greatest Common Factor of two numbers is the biggest number which divides both the given numbers completely.

Now, for the expressions $x^{6}$ and $x^{3}$ :

Since, $x^{3}$ divides both the expressions completely and it is the biggest expression which divides both the expressions.

Therefore, $x^{3}$ is the Greatest Common Factor of $x^{6}$ and $x^{3}$

7 0

4 years ago

Read 2 more answers

ANSWER ASAP PLEASE FOR BRAINLIEST explanation please

vfiekz [6]

Answer:

You have to multiply all the sides by 4.

B to C = 2.8*4

2.8 * 4 = 11.2

B to A = 3*4

3*4 = 12

A to C = 2.2*4

2.2*4 = 8.8

Hope this helped!

7 0

4 years ago