What is the solution of the inequality shown below? c + 9 greater than or equal to 1

Mathematics

1 answer:

kykrilka [37]3 years ago

5 0

Answer:

c ≥-8

Step-by-step explanation:

I got this answer because all you have to do is subtract 9 on both sides and then that is the answer.

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<h2>Hello!</h2>

The answer is:

The ball will hit the ground after $t=2.47s$

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So,

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

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Then, substituting it into the quadratic equation, we have:

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s$