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3 years ago

Solve for x .. please hurry

Mathematics

1 answer:

defon3 years ago

7 0

Step-by-step explanation:

4x+x-1+2x+1

since any number power zero is one

group like terms

4x +x+ 2x-1+1

7x=0

divide both sides by 7

x= 0

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Please help me with correct answer

BaLLatris [955]

D. -15

All I did was plug the numbers in

4 0

3 years ago

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT. Find m2C in the quadrilateral.

saul85 [17]

Answer:

m∠C = 107°

Step-by-step explanation:

there are 4 sides so we first need to find the total interior angle:

( 4 - 2 ) * 180 = 360°

m∠C = 360° - 90° - 90° - 73°

= 107°

8 0

3 years ago

Solve for m. m=-(4+m)+2

pishuonlain [190]

Answer:

m= -1

Step-by-step explanation:

Order summands

Apply negation to the value inside parentheses

Add the numbers

Add

to both sides of the equation

Simplify

3 0

3 years ago

Read 2 more answers

Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum

lara [203]

Answer:

Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

$\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\$

$\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\ (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\$

$=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3} \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\$

4 0

2 years ago

Determine whether the fractions 3 4 and 4 5 are equivalent. Question content area bottom Part 1 Select the correct choice below

VMariaS [17]

Answer: Choice A

The fractions are not equivalent because the product of the numerator of the first fraction and the denominator of the second fraction is <u> 15 </u> , which is not equal to the product of the numerator of the second fraction and the denominator of the first fraction <u> 16 </u>

===================================================

Explanation:

We have the template $\frac{P}{Q} = \frac{R}{S}$ which cross multiplies to $PS = QR$

So if $\frac{3}{4} = \frac{4}{5}$ was true, then $3*5 = 4*4$ must be true as well, and vice versa.

The left side 3*5 turns into 15, while the right hand side 4*4 becomes 16. The 15 and 16 don't match up.

In short, $3*5 = 4*4$ turns into $15 = 16$ which is a false statement. So the original claim that $\frac{3}{4} = \frac{4}{5}$ is also false.

5 0

2 years ago