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Novosadov [1.4K]
3 years ago
10

Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le

ngth of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope, what is the maximum possible length, in centimeters, of the longest piece of rope?
Mathematics
1 answer:
Svet_ta [14]3 years ago
7 0

Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes  =68

Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}

68= \frac{\text{Sum of all lengths}}{7}

68 \times 7 =\text{a+b+c+d+e+f+g}

476=\text{a+b+c+d+e+f+g} --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

476=x+x+x+84+84+84+4x+14

476=7x+266

\frac{476-266}{7}=x

30=x

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

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Step-by-step explanation:

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It will take Shanti 150 square inches of paper to wrap the gifts

Step-by-step explanation:

Shanti wraps the gift she is taking to a friend's birthday party. She doesn't have very much paper, so she does not overlap any of the edges. The side lengths of the cube are all 5in.

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Solution

To solve this, you will find the surface area of a cube

Surface area of a cube = 6a^2

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0.25

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formula is y2-y1 / x2-x1

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The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?
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Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that r = 0.16

So

V(t) = V(0)(1-r)^{t}

V(t) = V(0)(1-0.16)^{t}

V(t) = V(0)(0.84)^{t}

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

V(t) = V(0)(0.84)^{t}

0.5V(0) = V(0)(0.84)^{t}

(0.84)^{t} = 0.5

\log{(0.84)^{t}} = \log{0.5}

t\log{0.84} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.84}}

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The half life of the car is 3.98 years.

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Answer:

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Step-by-step explanation:

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Sum of the roots :

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Product of the roots :

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= (-84)//

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